Electric motors & faraday's law

Click For Summary
SUMMARY

The discussion centers on the application of Faraday's Law in the context of a wire coil connected to a power supply and a multimeter. Eliza's setup demonstrates that only the bare part of the wire coil will conduct current, while the insulated section will not. The orientation of the coil relative to the magnetic field determines which end acts as the north or south pole. When the coil is placed above a magnet and the switch is closed, the interaction between the magnetic field and the current will dictate the coil's behavior.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of magnetic flux and its calculation
  • Familiarity with basic electrical components: power supply, switch, multimeter
  • Concept of magnetic poles and their orientation
NEXT STEPS
  • Study the application of Faraday's Law in electric motors
  • Learn about the principles of magnetic flux and its role in electromagnetism
  • Explore the behavior of coils in magnetic fields using simulations
  • Investigate the effects of coil orientation on induced electromotive force (EMF)
USEFUL FOR

Students studying electromagnetism, electrical engineers, and educators looking to explain the principles of electric motors and electromagnetic induction.

jackd
Messages
3
Reaction score
0

Homework Statement


Eliza connects a power supply, switch, and a multimeter (in ammeter mode) in series with a wire coil. The wire coil is held into place by 2 connecting wire leads. One of the wire leads has been stripped off of the insulating enamel coating so that half the wire is bare; the other lead has been completely stripped bare.

1. What orientations of the coil will give a current through it due to the battery?

2. During the time that there is a current through the coil, which side of the coil will act like a north pole and which side will act like a south pole? Explain?

3. How will the coil behave when placed above the magnet and the switch is closed?


Homework Equations


Faraday's Law: E=-d(magnetic flux)/dt
Magnetic Flux = B*Acos(\theta


The Attempt at a Solution


The part without coating will give a current, but the part that has coating will not?
Very lost...
 
Physics news on Phys.org
jackd said:
The part without coating will give a current, but the part that has coating will not?

Yes.

For the rest, it's hard to see what's going on without a figure.
 

Similar threads

Eddy currents in Faraday's Law Experiment
  • · Replies 3 ·
Replies
3
Views
2K
Making sense of sequence of ideas in MIT OCW's 8.02 notes on Faraday
  • · Replies 1 ·
Replies
1
Views
2K
Induced EMF in a circle: Faraday's law
  • · Replies 11 ·
Replies
11
Views
3K
EMF shielding using a conductor
  • · Replies 6 ·
Replies
6
Views
2K
Electromagnetic Induction of a Disk
  • · Replies 5 ·
Replies
5
Views
3K
Current in circular wire surrounding infinite solenoid in a circuit
  • · Replies 7 ·
Replies
7
Views
2K
Explaining the Decrease in Current in a Rotating Motor
  • · Replies 4 ·
Replies
4
Views
3K
How does an eddy current brake work exactly?
  • · Replies 2 ·
Replies
2
Views
3K
Lenz's Law and Faraday's Law clarification
  • · Replies 11 ·
Replies
11
Views
3K
Calculating Induced EMF using Faraday's Law: A Magnetic Flux Problem Solved
  • · Replies 5 ·
Replies
5
Views
4K