Electric Potential and Spheres

Click For Summary

Homework Help Overview

The discussion revolves around the electric potential of two unequally sized charged metal spheres connected by a wire. Participants are exploring the relationship between charge, potential, and the geometry of the spheres.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand why the potentials of the spheres are the same despite having different charges. Some participants explain that equilibrium in the wire leads to equal potential, while others question the implications of differing charges and radii on potential calculations.

Discussion Status

Participants are actively engaging with the concepts of electric potential and charge distribution. There is a productive exchange of ideas, with some clarifications being made regarding the definitions and implications of potential in the context of the problem.

Contextual Notes

There is a mention of differing radii for the spheres, which affects the potential calculations. Additionally, the original poster notes their background in AP Physics B, indicating a potential gap in familiarity with the topic of electric potential in spheres.

cjosephson
Messages
3
Reaction score
0
Two unequally sized metal spheres are each charged. A wire is connected from one sphere to the other. When the wire is removed, the spheres will have the same potential. T/F?

The answer is true (I looked up the key), but I do not understand why.

I know that the spheres, due to being unequally sized, have different charges. But I thought potential was EPE/q, which is (Qq/r)/q, which simplifies to Q/r. If the spheres have different charges, won't the potential always be different? Can someone help explain why the potentials would be the same?

Thanks!
 
Physics news on Phys.org
The spheres have the same potential because there can't be an electric field in the wire if the charges are in equilibrium and no current flows.

This means that the charge must distribute itself in such a way that the potential on the spheres is the same.

The potential of a sphere with radius r and charge Q is. [tex]\frac{Q}{4 \pi \epsilon_0 r}[/tex]

obviously Q depends on r
 
kamerling said:
The spheres have the same potential because there can't be an electric field in the wire if the charges are in equilibrium and no current flows.

This means that the charge must distribute itself in such a way that the potential on the spheres is the same.

The potential of a sphere with radius r and charge Q is. [tex]\frac{Q}{4 \pi \epsilon_0 r}[/tex]

obviously Q depends on r

OK, you explanation makes sense--there can be no potential difference because of the way the charges move. When they say potential, though, what do they mean? Because the charge Q is different for each of the spheres, clearly they don't mean the potential as from a distance R--if the Q's are different, and R is the same, the clearly Q1/R != Q2/R.

Sorry if my follow-up question is vague, I'm finding it hard to phrase.
 
they're unequally sized spheres, so R is NOT the same
 
Ah, I was thinking of R as the distance away from the spheres, not the radius of the spheres. I'm doing AP Physics B, so we don't really do very much with the potential of spheres, since it's a C subject. Please excuse me!
 

Similar threads

Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
11
Views
2K
Replies
12
Views
2K
  • · Replies 21 ·
Replies
21
Views
5K
Replies
23
Views
5K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
2
Views
771
Replies
5
Views
1K