Electric potential at certain point from charged sphere

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SUMMARY

The discussion centers on calculating the electric potential from a charged sheet using the formula V = (σX)/ε₀, where σ represents charge density and ε₀ is the permittivity of free space. It is clarified that this equation is strictly applicable to an infinite sheet of charge. The potential does indeed decrease as one moves away from the sheet, as demonstrated by the potential difference formula V = -σ(X2 - X1)/ε₀, confirming that the potential diminishes with increasing distance from the sheet.

PREREQUISITES
  • Understanding of electrostatics and electric potential
  • Familiarity with charge density concepts (σ)
  • Knowledge of the permittivity of free space (ε₀)
  • Basic grasp of potential difference calculations
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TheCammen
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Let's say I have a sheet of charge that is composed of a certain amount of charged atoms summing up to Q and a certain area A. The charge density would be Q/A = σ. I wish to find the elctrostatic potential from the sheet at point X. I believe that the electric potential should follow the equation:

V = (σX)/ ε_0

However, shouldn't the potential decrease as I travel away from the sheet? If I have a sphere of charge and I travel away from it, then this is the case. Why is this situation different?

EDIT: I meant sheet in the title ofthe post. I just had the sphere idea in my mind at the time!
 
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Hi TheCammen,

1. Strictly speaking, the relation is valid for an infinite sheet only .

2. The potential difference between two points , one at X1 and the other at X2 ( X2>X1) is

V=-σ(X2-X1)/ε0 ( pay attention to the minus sign). And as you see the potential does decrease as you travel away from the sheet.
 

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