Electric Potential Energy of a sphere

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Homework Help Overview

The problem involves calculating the work done to move a test charge in the electric field of a charged sphere. It specifically examines the electric potential energy associated with the movement of a charge from a distance of 100 m to 40 cm from the sphere.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of electric potential energy and the work done by electric fields, questioning the signs associated with work done by the electric field versus external forces.

Discussion Status

The discussion is exploring different interpretations of the work done in the context of electric forces. Some participants are clarifying the direction of forces and the implications of moving the charge closer to the sphere, while others are confirming their calculations and understanding of the problem setup.

Contextual Notes

There is a noted confusion regarding the distances involved in the problem, specifically the movement of the charge from 100 m to 40 cm, and the assumptions about the charge's nature and the resulting electric field direction.

mrxtothaz
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Homework Statement



A test charge of +1.0x10^-6 C is 40cm from a charged sphere of 3.2x10^-3 C. How much work was required to move it there from a point 1.0x10^2 m away from the sphere?

Homework Equations



W = \DeltaE
W = Ee2 - Ee1

The Attempt at a Solution



Ee2 = (9.0x10^9)(1.0x10^-6)(3.2x10^-3)/(0.4)
= 72

Ee1 = (9.0x10^9)(1.0x10^-6)(3.2x10^-3)/(100)
=0.288

W = 72 - 0.288
= 71.7
= 72 (significant digits)

I'm pretty sure my approach is correct, but I'm not sure if I should reverse the distance variables, since I would imagine it takes negative work to bring two like charges closer.
 
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In this case work done by the electric field is negative. But the work done by the external force is positive.
 
rl.bhat said:
In this case work done by the electric field is negative. But the work done by the external force is positive.

I think it's the other way around. Since there is no sign in front of the charge on the sphere, we must assume it is positive and the electric field generated by it must be radially out. This is also the direction of the (repulsive) electric force on the positive test charge. If the charge moves out from 40 cm to 100 m, the work done by the electric force is positive because the force doing the work and the displacement are in the same direction.
 
kuruman said:
I think it's the other way around. Since there is no sign in front of the charge on the sphere, we must assume it is positive and the electric field generated by it must be radially out. This is also the direction of the (repulsive) electric force on the positive test charge. If the charge moves out from 40 cm to 100 m, the work done by the electric force is positive because the force doing the work and the displacement are in the same direction.
In this problem charge is moved from 100 cm to 40 cm.
 
rl.bhat said:
In this problem charge is moved from 100 cm to 40 cm.
Yes, of course. I misread the problem.
 
I got the same answer that was posted.

To clarify the distance, the test charged is moved from a position 100 m away from the charged sphere to a position 40 cm away from the charged sphere.
 

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