Electric Potential Energy Question

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SUMMARY

The discussion revolves around calculating the electric potential energy of a three-charge system involving charges q1 (3x10^-6 C), q2 (1x10^-6 C), and q3 (-2x10^-6 C). The user initially calculated the total electric potential energy as -0.24 J using the formula E=(kq1q2)/r for each pair of charges but received a different answer of -0.12 J from their teacher. A suggested method for solving the problem involves calculating the work done by bringing each charge from an infinite distance, which clarified the user's misunderstanding and led to a correct approach.

PREREQUISITES
  • Understanding of electric potential energy and its calculation.
  • Familiarity with Coulomb's Law and the formula E=(kq1q2)/r.
  • Basic knowledge of charge interactions in electrostatics.
  • Concept of work done in bringing charges from infinity.
NEXT STEPS
  • Study the principles of electric potential energy in multi-charge systems.
  • Learn about the concept of work done in electrostatics and its applications.
  • Explore the implications of charge configuration on potential energy calculations.
  • Practice problems involving Coulomb's Law and electric potential energy for better understanding.
USEFUL FOR

This discussion is beneficial for high school physics students, educators teaching electrostatics, and anyone interested in mastering electric potential energy calculations in multi-charge systems.

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Hi, this is my first time posting here but I have a question that looked really simple at first, but the answer I get is wrong from the answer given to us by our teacher.
The question is this:
Consider the diagram below
http://img485.imageshack.us/img485/9282/physics3bn.jpg

a) What is the electric potential energy of the system?
What I did
3x10^-6=q1
1x10^-6=q2
-2x10^-6=q3

Epotental(total)= (Epotential @ q1) + (Epotential @ q2) + (Epotential @ q3)
=[(kq1q2)/0.36 + (kq1q3/0.36)] + [(kq2q1/0.36) + (kq2q3/0.4)] + [(kq3q1/0.36) + (kq3q2/0.4)]

I used the formula E=(kq1q2)/r to get the potential energies at all 3 points and then added them together. I got -0.24 J but the answer the teacher gave us is -0.12J. Is it possible he is mistaken, or am I oversimplifying this question?

BTW: This is grade 12 physics
 
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Try applying this method to a two-charge system and see if you can figure out what you're doing wrong. Here's how I would do a problem like this: I'd "move" one charge in from an infinite distance and calculate the work done, which is zero. Then I'd bring in the second and fix it in place and calculate the work done. Then I'd bring in the third charge, etc.
 
I tried what you recommended in your second part and it worked :)
Thanks.
 

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