Electric Potential from a uniformly charged sphere

  • Thread starter Oijl
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  • #1
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Homework Statement


A nonconducting sphere has radius R = 2.70 cm and uniformly distributed charge q = +7.00 fC. Take the electric potential at the sphere's center to be V0 = 0.

(a) What is V at radial distance r = 1.45 cm?

(b) What is V at radial distance r = R?

Homework Equations


E = Vdv
V = k (q / r)

The Attempt at a Solution


I was about to just integrate E from zero to r1 and then r2, but then I realized that as r increases, so does q so I can't just have a simple single integration. And then I didn't know what to do. Help? Thanks.
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
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Charge density in the sphere = ρ = Q/[4/3*π*R^3]
Charge enclosed in the sphere of radius r = ρ* volume of the sphere of radius r
Q' = { Q/[4/3*π*R^3]}*4/3*π*r^3
= Q*r^3/R^3
Using Gauss theorem, if the electric field E at a distance r is E, then
4πr^2E = Q/εο*r^3/R^3
Or E = 1/4πεο*Qr/R^3 = - dV/dr. Now find the integration.
 
  • #3
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Aaaaaahhhhhhhhhhhhh. Thank you so much! I do particularly thank you because you helped me recognize that I need to do much more variable rewriting than I've been doing.
 
  • #4
i had a problem in this question,
i got E = 1/4πεο*Qr/R^3 (using gauss law)
when i applied - dV/dr. , i could not got the answer,I used the basic defination of electric potential that said bring charge from infinity to that pt , i integrated it (-E.dr) from infinity to r,as evident i gt an infinite term in numerator ,plz help ???
 
  • #5
rl.bhat
Homework Helper
4,433
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I used the basic defination of electric potential that said bring charge from infinity to that pt , i integrated it (-E.dr) from infinity to r,as evident i gt an infinite term in numerator ,plz help ???

To find the potential at r, you have to consider the electric field outside and inside the sphere separately.
So V(r) = -int[1/4πεο*Q/r^2*dr] from infinity to R - int[1/4πεο*Qr/R^3*dr] from R to r.
 
  • #6
thanks :) but can you explain in detail that why we follow this approach and whats wrong with d other one?
 
  • #7
rl.bhat
Homework Helper
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Which one is the other approach?
You have tried to find the potential at r using the same expression for E from infinity to r. But it is wrong. Out side the sphere E = 1/4πεο*Q/r^2 and inside the sphere E = 1/4πεο*Qr/R^3. Using these expression find the integration to find the potential at r.
 

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