Electric potential of the arc of a circle

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SUMMARY

The discussion centers on calculating the electric potential of an arc of a circle, following the previously derived electric field equations: Ex = Q/2π²ε₀a²sin(θ) and Ey = Q/2π²ε₀a²(1-cos(θ). The user initially attempted to find the potential using V = E dr but recognized an error in their calculations. The corrected formula presented is V = kQ/a, which aligns with the potential of a point charge, confirming its validity in this context.

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  • Understanding of electric fields and potentials
  • Familiarity with calculus, particularly integration techniques
  • Knowledge of electrostatics, specifically Coulomb's law
  • Basic concepts of circular geometry in physics
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  • Review the derivation of electric potential from electric field equations
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madah12
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Homework Statement


I previously calculated the electric field for the the arc of the circle and got
Ex= Q/2pi^2 e_0 a^2 sin(theta)
Ey= Q/2pi^2 e_0 a^2 (1-cos(theta))

I need the electric potential

Homework Equations


The Attempt at a Solution


V=Edr
i got an answer interms of theta and since I know its wrong I won't waste time posting it so which is the best approach?
Edit: I guess I will just post the result to make sure its wrong v = Qtheta/2pi^2 *e_0 a
 
Last edited:
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uhm I see that I made an error in calculation now I have v=kQ/a which is the same as a point charge? is this wrong or right?
 
can anyone atleast tell me if the formula is correct or not?
 

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