1. The problem statement, all variables and given/known data d.c supply 200V capacitors A and B connected in series p.d across A is 120V p.d. across A, increased to 140V when a 3μF capacitor is connected in parallel with B. attached diagram for better understanding. Find capacitance of A and B. 2. Relevant equations C=Q/V Capacitance total in parallel connection = sum of 'n' numbers of capacitors Capacitance total in series connection for this case is = 1/Ct = 1/A + 1/(B+3) 3. The attempt at a solution Need help, really don't know where to start with 2 unknown capacitors value.