Engineering Electrical energy to empty reservoir with a siphon water pipe

AI Thread Summary
The discussion focuses on calculating the potential electrical energy generation from a siphon pipe draining an enclosed reservoir into a Pelton turbine with a 75% efficiency. Key parameters include a height difference of 4.5 meters, a total siphon length of 10.5 meters, and a maximum instantaneous power output of 245.24W. The average energy generated during the reservoir's emptying process is calculated to be 2940 joules, with a total time of approximately 81415.89 seconds to empty the reservoir. After accounting for various efficiency coefficients, the total energy output is estimated at 36.7 kWh. This analysis highlights the feasibility of using siphon systems for energy generation.
CalvinandHobbes
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Homework Statement
Calculation of potential electrical energy in a siphon water pipe
Relevant Equations
Ey=Eo x Vy/Vo x adjustment coefficients
Calculation of the potential electrical energy generation of a siphon pipe, emptying an enclosed reservoir and end of siphon pipe connected to a pelton turbine with efficiency of 75%
Known inputs:
Height difference of siphon(Hd) = 4,5m
Height lift of Siphon (Hu) = 6m
Total siphon pipe length 10.5m
Pipe internal diameter 28mm
Friction loss coefficient : 0.00184
Head loss at inlet resistance coefficient:0.464
Resistance coefficient at bend siphon: 1.4
Maximum instantaneous power from flow:245.24W
Minmum instantaneous power from flow:64.31W
Integral instantaneous power from flow:245.24W
Maximum Vacuum:8m
Average energy generation on emptying reservoir: 2940j
Time to empty reservoir: 81415.89s
Reservoir volume: 168.713m3
Reduction coefficient: 0.92
generator effeciency coefficient: 0.8
Turbine efficiency: 75%

Solution:
2940 x 81415.89/1000x.000277778 x 0.92 x 0.8 x .75 = 36.7kWh
 
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