Electrical energy to empty reservoir with a siphon water pipe

[CalvinandHobbes]

Homework Statement

Calculation of potential electrical energy in a siphon water pipe

Relevant Equations

Ey=Eo x Vy/Vo x adjustment coefficients

Calculation of the potential electrical energy generation of a siphon pipe, emptying an enclosed reservoir and end of siphon pipe connected to a pelton turbine with efficiency of 75%
Known inputs:
Height difference of siphon(Hd) = 4,5m
Height lift of Siphon (Hu) = 6m
Total siphon pipe length 10.5m
Pipe internal diameter 28mm
Friction loss coefficient : 0.00184
Head loss at inlet resistance coefficient:0.464
Resistance coefficient at bend siphon: 1.4
Maximum instantaneous power from flow:245.24W
Minmum instantaneous power from flow:64.31W
Integral instantaneous power from flow:245.24W
Maximum Vacuum:8m
Average energy generation on emptying reservoir: 2940j
Time to empty reservoir: 81415.89s
Reservoir volume: 168.713m3
Reduction coefficient: 0.92
generator effeciency coefficient: 0.8
Turbine efficiency: 75%

Solution:
2940 x 81415.89/1000x.000277778 x 0.92 x 0.8 x .75 = 36.7kWh

 

[Babadag]

See:

https://res.mdpi.com/d_attachment/energies/energies-13-04848/article_deploy/energies-13-04848-v2.pdf