Electrical Force Decreased by 1/4 When Particles Moved Half as Far Apart

weemanbran
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Homework Statement


The magnitude of electrical force between a pair of charged particles is _____ as much when the particles are moved half as far apart.


Homework Equations





The Attempt at a Solution



I understand that Coulomb's Law is.

F = k q1 q2 / d^2

So is the answer just putting in the distance which is 1/2 and squaring it? So is it just 1/2^2?
 
on Phys.org
Be careful -- the distance between particles appears in the denominator of Coulomb's Law. So if the distance is halved, what happens to this ratio?
 
If the distance distance is halved then the ratio would increase... I just don't know by how much...
 
Will the force increase or decrease? and by what factor? Hint: What is [tex](\frac{1}{2})^2[/tex]?
 
konthelion said:
Will the force increase or decrease? and by what factor? Hint: What is [tex](\frac{1}{2})^2[/tex]?

I think you mean [tex]\frac{1}{(\frac{1}{2})^2}[/tex] ; the halved distance is in the denominator for Coulomb's Law...
 

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