Electromagnetic Waves Problem -

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SUMMARY

The discussion centers on calculating the electric field amplitude of a 200 MW laser pulse focused to a diameter of 2.0 micrometers and comparing it to the electric field binding an electron to a proton in a hydrogen atom. The user successfully calculated the electric field amplitude at the focal point as 2.19×10^11 V/m using the formula E = sqrt((2 * I) / (c * epsilon_0)). For Part B, the user initially attempted to find the electric field using the radius of the electron's orbit (0.053 nm) but needed clarification on applying the correct formula for a point charge, E = q/(4π ε₀ r²).

PREREQUISITES
  • Understanding of electromagnetic wave properties
  • Familiarity with laser power and intensity calculations
  • Knowledge of electric field equations, particularly for point charges
  • Basic concepts of atomic structure, specifically hydrogen atom electron orbits
NEXT STEPS
  • Study the derivation and application of the electric field equation for point charges
  • Explore the relationship between intensity and electric field in electromagnetic waves
  • Learn about the properties of laser beams and their focusing techniques
  • Investigate the quantum mechanics of electron orbits in hydrogen atoms
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the properties of electromagnetic waves and atomic interactions.

ashkash
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A 200 MW laser pulse is focused with a lens to a diameter of 2.0 micrometers.

Part A:
What is the laser beam's electric field amplitude at the focal point?

Part B:
What is the ratio of this electric field to the electric field that keeps the electron bound to the proton of a hydrogen atom? The radius of the electron's orbit is 0.053 nm.


I was able to get Part A correct. I used I = P/A to find the intensity using the power and area and then used E = sqrt( (2* I) / (c * epsilon_0)) to find the amplitude of the electric field and I got a numerical value of 2.19×10^11 V/m.

Part B is where I need help. I tried finding the electric field like I did in part A using the new radius given (0.053 nm) and then divided my answer from part A by this to get the ratio, but this does not work. What am I doing wrong?
 
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You got the hard part! Part B is much simpler. Use the standard electric field equation for a point charge: E=q/(4pi epsilon r^2)
 
thanks for the help.
 

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