Electromagnetism: Trouble understanding the D field

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SUMMARY

The discussion focuses on the electric displacement field (D) in the context of an undergraduate electromagnetism course using Wangsness as a textbook. The D field is crucial for determining the electric field (E) within dielectrics, particularly when the surface charge distribution is known. It is established that D is proportional to the surface charge density, allowing for the calculation of E in specific configurations, such as parallel plate capacitors with dielectrics in series. However, the method is not applicable for dielectrics in parallel due to changes in surface charge distribution.

PREREQUISITES
  • Understanding of electric fields and dielectrics
  • Familiarity with the concept of surface charge density
  • Knowledge of Gauss's Law
  • Basic principles of capacitors and their configurations
NEXT STEPS
  • Study the relationship between electric displacement field (D) and electric field (E) in dielectrics
  • Learn about the bound charge and its calculation using polarization (P)
  • Explore the applications of Gauss's Law in determining surface charge density
  • Investigate the differences between dielectrics in series and parallel configurations
USEFUL FOR

This discussion is beneficial for undergraduate physics students, particularly those studying electromagnetism, as well as educators seeking to clarify concepts related to electric displacement fields and dielectrics.

BeBattey
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I've just finished my first term in an undergrad electromagnetism course using Wangsness as a textbook and we ended on the displacement field.

I feel like Wangsness doesn't give a very good explanation of what the whole point of it actually is, and I still don't quite understand how to use it to find the e field inside both a dielectric and a cavity within a dielectric.

If I could get a quick and easy explanation or a point in the right direction I'd greatly appreciate it, thanks!
 
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Hi BeBattey! :smile:

The electric displacement field (D, measured in coulombs per square metre) is helpful if you know the surface charge distribution (because it's proportional to it).

So if you know the surface charge distribution, that gives you D, and you can immediately find E for different dielectric fillings, provided inserting the dielectric does not alter the surface charge distribution.

So it works eg for a parallel plate capacitor with dielectrics in series (and with edges parallel to the plates), but not for dielectrics in parallel (because the surface charge distribution will change).
 
Thanks for the response!

So the surface charge density you're talking about, is that the bound charge mentioned in the textbook? I know the bound surface charge is P dot n-hat, given the polarization of a dielectric, is this what you mean about the proportionality?
 
Hi BeBattey! :smile:

I was really thinking about those exam questions where you know the surface charge, either because the question specifically tells you, or because eg it's a sphere and you can use gauss, or it's a capacitor and you know C V and A (area), so you can find σ = Q/A (and D = σñ).
 

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