Electron confined to a rectangle with walls

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Homework Help Overview

The discussion revolves around the quantum mechanics problem of an electron confined to a rectangular area with infinitely high walls, exploring the calculation of its ground state energy. Participants are considering whether this scenario can be treated similarly to a two-dimensional box problem as described in quantum mechanics literature.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are examining the implications of treating the rectangular confinement as a 2D box, questioning the validity of this approach given the problem's specifications. There are inquiries about deriving energy levels and comparing photon wavelengths to visible light spectra, as well as requests for elaboration on specific equations and their origins.

Discussion Status

The conversation is active, with participants seeking clarification on various aspects of the problem, including the derivation of energy equations and the relationship between energy levels and photon wavelengths. Some guidance has been offered regarding the treatment of the problem as a classic introductory quantum mechanics scenario, but no consensus has been reached on specific methods or interpretations.

Contextual Notes

Participants are navigating the nuances of quantum mechanics, particularly in relation to the assumptions about potential energy and confinement in two dimensions. There are references to specific constants and values, indicating a focus on practical calculations within the context of the problem.

quantum_prince
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An electron is confined to a rectangle with infinitely high walls.I need to calculate the ground state energy of the electron.

Can I treat a rectangle with infinite high walls to be the same as 2d box as mentioned here.

http://en.wikipedia.org/wiki/Particle_in_a_box

or it should be treated in some other way.

The problem mentions rectangle and not rectangular box as such, but since high walls are mentioned I thought it should be treated as 2d.

Will this apply for rectangle with high walls?.

For the 2-dimensional case the particle is confined to a rectangular surface of length Lx in the x-direction and Ly in the y-direction.


I think infinite high walls is mentioned only to inform us that the potential is zero inside the rectangle and infinite at the walls. If the rectangle had side lengths in nanometers can we still treat it as a 2-dimension box problem.

Regards.
QP.
 
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It is a 2D box if the walls are infinite.
 
Thanks.

How can I figure this out to compare the wavelength of a photon emitted in a transition from the first excited state to the ground state with the spectrum of visible light in such a box.
 
The evs are just the sum of two 1D evs.
Then use hf=E12-E11.
 
Hi,

Could you elaborate a bit more.I don't follow.

Regards.
QP
 
The energy levels are
[tex]E_{mn}= \frac{h^2}{8M}\left[\left(\frac{m}{L_x}\right)^2<br /> +\left(\frac{n}{L_y}\right)^2\right].[/tex]
Then hf=E12-E11.
 
How did you derive this equation?.Can you post me a link of where you got this from.

Regards.

QP.
 
Which kind of lecture course are you being asked to tackle this problem? I would say this is a classic introductory quantum mechanics problem - one of the first I remember looking at anyway. This question is the same as the box where the side-wall potentials aren't infinite and in fact it is actually easier. To derive the formula Meir Achuz has given is very instructive - you will no-doubt be asked to find similar results for various types of potentials and as such I would strongly recommend getting your notes/textbook out and attempting to work through it.
 
quantum_prince said:
How did you derive this equation?.Can you post me a link of where you got this from.

Regards.

QP.
You could just look at your Wikipedia and add the two 1D eigenvalues given there.
 
  • #10
Hi Meir,

I use the following formulae.

[tex]\lambda = \frac{hc}{E12-E11}[/tex]

In such a case

I have [tex]\lambda = \frac {8McL_y^2}{3h}[/tex]

Taking Mass of electron as 9*10^31 kg

c as 3*10^8 m/sec Ly as 400nm and h as 6.634*10^-34, I get

[tex]\lambda = 0.16 m[/tex] which is huge where as most of the wavelengths we see are in between the range of 400-800nm.How would this be possible?.

As I understand h in your equation is the same as h what I have in what equation I have with me.You have used Planck's constant instead of dirac constant right?.

Regards.
Q.P
 
Last edited:

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