Projectile Motion in an Electric Field

[rlc]

y=(vt(sinθ))−0.5gt^2
y=((5.15E6 m/s)(7.77e-9 s)) - 0.5(8.78E14 m/s^2)(7.77e-9 s)^2
y=0.0135 m

I just checked this, and this is the correct answer (! yay!). Why is the 0.04 not involved in this last step like I thought? Is it because it is involved in the calculation for Tx, which is the time we used for this part?

 

[haruspex]

Why is the 0.04 not involved in this last step like I thought? Is it because it is involved in the calculation for Tx, which is the time we used for this part?

Yes.

 

[rlc]

Thank you very much for helping me through this problem. I probably wouldn't have found those mistakes if you hadn't pointed them out to me.