The Problem: An electron moves with speed 9.00 105 m/s in a uniform magnetic field of 2.0 T, pointing south. At one instant, the electron experiences an upward magnetic force of 2.00 10-14 N. In what possible directions might the electron be moving at that instant? Give your answers as angles clockwise from south (from 0° to 360°), in increasing degrees. The only equation needed should be F= lql * VBsin(theta) I used the above equation and found the angle to be 3.98° counterclockwise of South. So my first answer was 360-3.98=356.02° (which was correct). My problem came with finding the angle at the second position. I initially thought that it would be 180-3.98, but, through guess work, I found that the correct answer is 180+3.98= 183.98. I'm not sure why this is right. Can someone help me understand the concept behind the second possible position of the electron? Thank you!