Hi, I have a problem working out the answer to one part of a type of uniform field question. My answers to the first three parts of the question are correct, but I'll write out those parts as well because I think it's necessary, to understand the second part: An X-ray tube is operated at 25 kV and draws a current of 3 mA (a) Calculate: (i) the kinetic energy of each electron as it hits the target ( Answer: 4x10-15 J ) (ii) the velocity of impact of the electron as it hits the target ( Answer : 9.38x107 m s-1 (iii) the number of electrons hitting the target each second ( Answer : 1.875x1016 electrons ) The following part is the part I'm having difficultly on: (b) What happens to the kinetic energy of the electrons? My guess was it changed to electrical potential energy, but I don't think that is correct because that's what it would have if it was at the negative plate of a uniform field, but this electron must be at the positive end because it gained kinetic energy. Sorry to bother you all with this problem, I should know the answer but I'm just not sure what the question wants from me, I would consult the answer sheet but it only provides the answers for questions with numerical solutions. Thanks in advance for any correspondence.