Electron's Speed in Field and Charge

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SUMMARY

The discussion focuses on the calculations involving an electron's speed in a uniform electric field of 1.25 kN/C and the number of electrons required to produce a charge of 125 nC. The calculated final speed of the electron after 20 ns is approximately 4.39 x 10^6 m/s, derived using the equations v_f = v_i + a*t and a = (E*q_e)/m_e. Additionally, to achieve a charge of 125 nC, approximately 7.81 x 10^11 electrons must be transferred, calculated using the formula Total q / q_e.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with basic kinematics equations
  • Knowledge of charge quantization and elementary charge (q_e)
  • Proficiency in unit conversions (e.g., from nanocoulombs to coulombs)
NEXT STEPS
  • Study the relationship between electric fields and particle acceleration
  • Learn about the implications of charge transfer in electrostatics
  • Explore advanced kinematics involving relativistic speeds
  • Investigate the properties of electrons and their behavior in electric fields
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Students in physics, educators teaching electromagnetism, and anyone interested in the dynamics of charged particles in electric fields.

Soaring Crane
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Homework Statement



An electron is released from rest in a uniform electric field of 1.25 kN/C. After 20 ns, the electron's speed will be approximately


a. 2.5 x 10^-5 m/s

b. 3.9 x 10^3 m/s

c. 3.0 x 10^8 m/s

d. 2.5 x 10^3 m/s

e. 4.4 x 10^6 m/s




Homework Equations



Vector E = (m_e*a)/q_e

v_f = v_i +a*t


The Attempt at a Solution



a = (E*q_e)/m_e = [(1250 N/C)*(1.60*10^-19 C)]/(9.11*10^-31 kg) = 2.1954*10^14 m/s^2

v_f = v_i +a*t, where v_i = 0 m/s

v_f = a*t = (20*10^-9 s)*(2.1954*10^14 m/s^2) = 4.39*10^6 m/s (E.) ?



Homework Statement



How many electrons must be transferred to a body to produce a charge of 125 nC?

a. 1.25 10^-7
b. 7.81 10^11
c. 1.28 10^12
d. 3.45 10^11



Homework Equations



Total q / q_e = # of electrons

The Attempt at a Solution



(125*10^-9 C)/(1.60*10^-19 C) = 7.813*10^11 electrons ?

Thanks.
 
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Both correct as far as I can see.
 

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