Electrostatic energy of a dielectric sphere

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SUMMARY

The discussion focuses on calculating the electrostatic energy of a neoprene sphere with radius R, charged with a total charge Q uniformly distributed on its surface. The user attempts to compute the displacement field using the expression U = ∫ D·E dV, but encounters difficulties in determining the electric field inside the sphere, where D equals zero due to the absence of free charges. It is established that if D is zero, the electric field E is also zero within the sphere, assuming neoprene behaves as a linear dielectric.

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  • Understanding of electrostatics and electric fields
  • Familiarity with the concepts of displacement field (D) and electric field (E)
  • Knowledge of dielectric materials and their properties
  • Basic calculus for evaluating integrals in electrostatic energy calculations
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  • Learn how to calculate the polarization vector P in dielectric materials
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  • Investigate the behavior of electric fields in spherical geometries
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libelec
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1. Find the electrostatic energy of a neoprene sphere or ratio R, charged with Q if:

a) Q is uniformly distributed in surface



The Attempt at a Solution



So, I can calculate the displacement field (so that I can use the expresion U= \int \vec{D}.\vec{E} dV), but only for those points in space where r>R. Then, given that D=\epsilonE, I can find the electric field for r>R.

But I don't know how to get the electric field inside the sphere, since D=0 there because there're no free charges inside. It could also happen that E doesn't exist inside the sphere either, but I woundn't know the reason why.

Any ideas? Thanks.
 
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Anybody?
 
Does anybody know how I can get P of polarization?
 
libelec said:
[
So, I can calculate the displacement field (so that I can use the expresion U= \int \vec{D}.\vec{E} dV), but only for those points in space where r>R.

How are you calculating the displacement field? And why can't you calculate it for r\leq R?

Then, given that D=\epsilonE, I can find the electric field for r>R.

doesn't \epsilon=\epsilon_0 for r>R?

But I don't know how to get the electric field inside the sphere, since D=0 there because there're no free charges inside. It could also happen that E doesn't exist inside the sphere either, but I woundn't know the reason why.

You've already given the reason why...just assume that neoprene is a linear dielectric, then you know \textbf{D}=\epsilon\textbf{E}, so if \textbf{D}=0, then so does the electric field!
 
Yes, thank you. I thought I had to find the polarization vector P.
 

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