Electrostatics: Creating Charged Objects

Click For Summary

Homework Help Overview

The discussion revolves around calculating the number of electrons needed to change the charge of an iron arrowhead from a positive value to a negative value, specifically from 2.100 μC to -2.82 μC. The problem involves concepts from electrostatics, particularly charge and electron transfer.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore different methods to calculate the number of electrons needed, including direct subtraction of charges and considering the need to neutralize the initial positive charge before achieving the desired negative charge.

Discussion Status

Multiple interpretations of the charge difference have been discussed, with some participants suggesting a need to clarify the calculation of total charge change. Guidance has been offered on how to correctly approach the problem, including breaking it down into steps involving neutralization and further charge adjustment.

Contextual Notes

Participants express concern about the accuracy of their calculations and the limited number of attempts allowed for homework submission. There is an emphasis on ensuring the correct interpretation of charge signs in the calculations.

Snape1830
Messages
65
Reaction score
0
An iron arrowhead has an initial charge of 2.100e-6 C. How many electrons are required to give it a charge of −2.82 μC?

I know that e (the elementary charge) = +/- 1.602E-19 C
And N is the number (or excess charge)

I tried solving this problem 2 ways. The first way:

(2.100E-6 - 2.82E-6)/1.602E-19
I got 4.45E12 electrons

The second way I did:
2.100E-6-1.602E-19 * N = -2.82E-6
-1.602E-19 * N = -2.82E-6 - 2.100E-6
N =-4.92E6/-1.602E19
N= 3.05E25 electrons

However, my homework says it's wrong I tried typing them in with a negative sign, it's wrong. I tried rounding to the nearest electrons, still wrong.
What am I doing wrong? I really have no idea!
 
Physics news on Phys.org
Snape1830 said:
An iron arrowhead has an initial charge of 2.100e-6 C. How many electrons are required to give it a charge of −2.82 μC?

I know that e (the elementary charge) = +/- 1.602E-19 C
And N is the number (or excess charge)

I tried solving this problem 2 ways. The first way:

(2.100E-6 - 2.82E-6)/1.602E-19
I got 4.45E12 electrons

The second way I did:
2.100E-6-1.602E-19 * N = -2.82E-6
-1.602E-19 * N = -2.82E-6 - 2.100E-6
N =-4.92E6/-1.602E19
N= 3.05E25 electrons

However, my homework says it's wrong I tried typing them in with a negative sign, it's wrong. I tried rounding to the nearest electrons, still wrong.
What am I doing wrong? I really have no idea!

The arrowhead initially has a positive charge. The first 2.100×10-6 C worth of electrons are needed to neutralize the initial positive charge.
 
You begin with a charge of 2.1e(-6) C. You need to add electrons until you have a charge of -2.82e(-6) C. This means you need to add enough electrons such that the total charge of all the electrons added is equal to the difference in these charges; that is, the total charge of all the eletrons you add must be [2.1e(-6) - (-2.82e(-6)] C.
 
SammyS said:
The arrowhead initially has a positive charge. The first 2.100×10-6 C worth of electrons are needed to neutralize the initial positive charge.

So would I divide 2.100E-6 by -1.602E-19?
 
Tsunoyukami said:
You begin with a charge of 2.1e(-6) C. You need to add electrons until you have a charge of -2.82e(-6) C. This means you need to add enough electrons such that the total charge of all the electrons added is equal to the difference in these charges; that is, the total charge of all the eletrons you add must be [2.1e(-6) - (-2.82e(-6)] C.

So 7.27E-7. What do I do from there?

I only have a couple tries left on my homework and I want to get it right.
 
I believe you have found the difference in charge incorrectly; you did 2.1e(-6) - 2.82e(-6) but you need to make it 2.1e(-6) - (-2.82e(-6)) so that it becomes addition and you get:

2.1e(-6) + 2.82e(-6) = 4.92e(-6) C

So the total number of electrons required woul have charge equal to 4.92e(-6). So what would you do next?

[Another way to think about it is that you need x electrons to reduce the charge from 2.1e(-6) to 0 and then another y electrons to reduce the charge from 0 to -2.82e(-6). If you sum x and y together you should find the same number as you will from the method I explained above.]
 
Tsunoyukami said:
I believe you have found the difference in charge incorrectly; you did 2.1e(-6) - 2.82e(-6) but you need to make it 2.1e(-6) - (-2.82e(-6)) so that it becomes addition and you get:

2.1e(-6) + 2.82e(-6) = 4.92e(-6) C

So the total number of electrons required woul have charge equal to 4.92e(-6). So what would you do next?




[Another way to think about it is that you need x electrons to reduce the charge from 2.1e(-6) to 0 and then another y electrons to reduce the charge from 0 to -2.82e(-6). If you sum x and y together you should find the same number as you will from the method I explained above.]

Wouldn't I divide that number by e? Then I get 3.07E13 electrons.
 
Yes, that is correct. You can try it the second way I mentioned to convince yourself that they are equivalent.
 
Tsunoyukami said:
Yes, that is correct. You can try it the second way I mentioned to convince yourself that they are equivalent.

I was holding my breath as I typed it into my answer key, waiting for the check! Thanks so much! I really appreciate it!
 
  • #10
I'm glad to have been of assistance. Hopefully you've learned something from this. :)
 

Similar threads

Replies
12
Views
3K
Replies
1
Views
6K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
11
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
34K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K