Elementary probability question: dice roll

In summary, the question asks for the probability of success or failure in 12 rolls of a single honest dice, where success is defined as rolling a 4 or 1, and failure is defined as not rolling a 1 or 4. The solution involves calculating the probability of not rolling a 1 or 4 in each individual roll and multiplying them together. This gives the probability of failure, and the probability of success can be calculated from this.
  • #1
Mathman2013
23
1

Homework Statement



Lets say you role a single honest dice 12 times. Where succes is either if the die shows 4 og 1 eye.

My question is what is the probability of sucess or failure?

Homework Equations

The Attempt at a Solution


Is it binomial or conditional probability?
 
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  • #2
It is not clear to me what question you are asking. Please quote the problem exactly as given.
 
  • #3
You roll one die 12 times if the die shows either 4 or a 1 it is success if it shows non 1 or non 4 for the remaining rolls then its a failture.

What is the probability of success or failure during the 12 rolls?
 
  • #4
You are still not explaining what probability you are after very well. Are you after the probability of success/failure in one particular roll? If not, what do you consider success/failure during the 12 rolls?
 
  • #5
So is it a success if we get a 1 or 4 on the first roll (not needing to roll anymore)? Is it also the same success if we fail 11 times and roll a 4 or 1 on the last roll?

If that is what you want, then you can do something like this: (prob of NOT rolling 1 or 4) AND (prob of NOT rolling 1 or 4) AND . . . AND (prob of NOT rolling 1 or 4).
Turn each of those AND's into multiplication, and assign a number for (prob of NOT rolling 1 or 4), and you have the probability that it will fail (Not rolling a 1 nor a 4 in 12 rolls).

Once you have that, calculating probability of success is straightforward.
 

1. What is the probability of rolling a specific number on a single six-sided dice?

The probability of rolling a specific number on a single six-sided dice is 1/6 or approximately 16.67%.

2. What is the probability of rolling a certain combination of numbers on two six-sided dice?

The probability of rolling a certain combination of numbers on two six-sided dice is calculated by dividing the number of desired outcomes by the total number of possible outcomes. For example, the probability of rolling a total of 7 on two dice is 6/36 or 1/6.

3. How many outcomes are possible when rolling two six-sided dice?

When rolling two six-sided dice, there are 36 possible outcomes. This can be calculated by multiplying the number of outcomes on the first dice (6) by the number of outcomes on the second dice (6).

4. What is the probability of rolling a higher number on the second roll of two six-sided dice?

The probability of rolling a higher number on the second roll of two six-sided dice is 5/6 or approximately 83.33%. This is because there are only 6 possible outcomes on the first roll, and 5 of those outcomes will result in a higher number on the second roll.

5. Can the outcomes of rolling a dice be predicted?

No, the outcomes of rolling a dice cannot be predicted with certainty. While the probability of each outcome can be calculated, the actual outcome is random and cannot be predetermined.

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