Elementary Thermodynamics Question

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SUMMARY

The discussion focuses on a thermodynamics problem involving a freezer containing 20 kg of food with a specific heat of 2000 J/kg°C. The freezer's motor operates for 10 minutes, reducing the temperature from -5°C to -8°C, resulting in a heat removal of -120,000 J. The energy delivered to the motor during this period is calculated as 240,000 J, leading to a total heat ejection of 360,000 J into the room. The main point of contention is the temperature change in the room, where the user calculates approximately 6.2°C, while the instructor states the correct answer is 7.3°C.

PREREQUISITES
  • Understanding of specific heat capacity and its formula Q = cmΔT
  • Knowledge of energy transfer in thermodynamic systems
  • Familiarity with the concept of heat ejection and energy conservation
  • Basic principles of thermodynamics, including heat transfer and temperature change
NEXT STEPS
  • Review the calculations for heat transfer in thermodynamic systems
  • Study the concept of significant figures in thermodynamic calculations
  • Learn about energy conservation principles in closed systems
  • Explore the effects of specific heat on temperature changes in various materials
USEFUL FOR

Students studying thermodynamics, educators teaching heat transfer concepts, and anyone interested in understanding energy dynamics in refrigeration systems.

Steven925
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The prompt for the question I am seeking help on is:

"A freezer contains 20 kg of food with a specifit heat of 2x10^3 J/kg*c. The temperature inside the freezer is initially -5*C. The freezer motor them operates for 10 minutes, reducing the temperature to -8*C."

I have found solutions to the first three portions of the question:
a)How much heat is removed from the food during this time? The freezer operates at 400W

Q = -120,000J using Q = CM(t(f) - t(i))

b)How much energy is delivered to the freezer motor suring the 10 minute period?

P = W/T = 240,000J

c)During this time, how much total heat is ejected into the room in which the freezer is located?

Q = Q + W = 360,000J

----------------

D is what i need help on:

"Determine the temperature change in the room if the specific heat of air is 700J/Kg*C. assume there are 80 kilograms of air in the room, the volume of the air is constant, and there is no heat loss from the room"

I have tried using the standard Q = cm(delta)t:

360,000J = 700J/Kg*c * 80 (delta)t

but that comes out to approximately 6.2 degrees celsius. My instructor says the answer is 7.3*C and I'm unsure of what I may be doing incorrectly. Any guidance would be greatly appreceiated.

Thanks!
 
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hrmmm. I tried doing mcAt = mcAt...

but it doesn't seem to work. lol
 
Steven925 said:
I have tried using the standard Q = cm(delta)t:

360,000J = 700J/Kg*c * 80 (delta)t

but that comes out to approximately 6.2 degrees celsius. My instructor says the answer is 7.3*C and I'm unsure of what I may be doing incorrectly. Any guidance would be greatly appreceiated.

Thanks!
I don't see anything wrong with your method. I get 6.4 deg. C which to the correct significant figures should be 6 deg. C.

AM
 

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