Empirical and Molecular Forumla calculation

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SUMMARY

The discussion focuses on calculating the empirical and molecular formulas of reductic acid, which contains 52.63% carbon, 5.30% hydrogen, and 42.07% oxygen by mass. The empirical formula is determined to be C5H6O3. To find the molecular formula, users are instructed to calculate the number of moles in 1.23 g of reductic acid and compare it to the given number of carbon atoms (3.25x10^22). The final step involves using Avogadro's number to calculate the mass of one molecule of reductic acid.

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Homework Statement



Reductic acid contains 52.63% carbon, 5.30% hydrogen and 42.07% oxygen by mass.
a) Determine the empirical formula of reductic acid

b) If 1.23 g of reductic acid contains 3.25x10^22 atoms of carbon, what is the molecular formula of reductic acid ?

c) Calculate the mass of one molecule of reductic acid.


Homework Equations



-

The Attempt at a Solution



I already found that the empirical formula and found that to be C5H6O3. But I can't seem to get the other parts. Thanks for the help.
 
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Use the molecular mass of the empirical formula to find the number of carbon atoms that there would be in 1.23 g and then compare this to the actual number of carbons given in the problem

e.g.

1.23 g ( moles / g = MW of C5H6O3 ) = moles of C5H6O3

convert this to atoms of C5H6O3 and then this to atoms of Carbon = x

3.25 X 10 ^ 22 atoms of carbon / x = the number factor to multiply your empirical formula to find the molecular formula.




For the next part simply use Avogadro's number.
 

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