Energy conservation of a sliding block

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Homework Help Overview

The discussion revolves around the energy conservation principles applied to a block sliding down an inclined ramp. The block has a specified mass, initial speed, ramp angle, and coefficient of kinetic friction, with the goal of determining the distance it slides before coming to rest.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss calculations involving normal force, frictional force, and energy terms. There is a focus on the correct application of energy conservation equations and the role of distance in these calculations. Some participants question the placement of distance in the energy equations and the interpretation of initial and final energies.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's calculations and interpretations. Some guidance has been offered regarding the correct formulation of energy equations and the need to consider the geometry of the incline. Multiple interpretations of the problem are being explored, particularly concerning the relationship between vertical and inclined distances.

Contextual Notes

Participants note that there may be confusion regarding the definitions of initial and final energies, as well as the role of work done by non-conservative forces. There is an acknowledgment of the need to clarify the relationship between the distance traveled down the incline and the vertical distance.

simmonj7
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Homework Statement


An 8.77-kg block slides with an initial speed of 1.58 m/s down a ramp inclined at an angle of 28.5° with the horizontal. The coefficient of kinetic friction between the block and the ramp is 0.69. Use energy conservation to find the distance the block slides before coming to rest.



Homework Equations


E = U + K
Non conservative force = E final - E intial


The Attempt at a Solution



So I first calculated the normal force by doing N = mg cos 28.5 and found that the normal was 75.6079 N.
Then, I knew the frictional force was equal to [tex]\mu[/tex] times the normal vector so I computed that and found that this force was equal to 52.169 N.

Now I calculated E final and E initial. I figured E initial would be (1/2)mv[tex]^{2}[/tex] (U would equal 0 because d=0 initially) where v is in initial velocity stated in the problem and got that this equaled 10.9467. I figured E final would be mgd where d is the final distance we are solving for (K equals 0 because the final velocity is zero since it comes to rest) so I got this equaled 86.0337d.

Then I figured since the frictional force is the non conservative force, I would set that equal to the final energy minus the initial energy so I would get 52.169 = 86.0337d - 10.9467 so I get d = .734.

However, this apparently isn't even close to the right answer. Where am I going wrong? Any help please?
 
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Wnc is (mu)(normal)(d)

Why is your d in the Efinal term? It should be in your first term.

D=(86.03-10.95)/52.169
 
simmonj7 said:
2. Homework Equations

Non conservative force = E final - E intial
This equation is wrong. The difference of energy is work or energy, not force.
 
I now see that I copied that equation wrong. I did compute the work of the frictional force not just the force and I still have the wrong answer.

But no d should not be in my E initial because at the initial point the object has not moved. Hence the distance is zero.
 
Last edited:
And the equation you provided for d is also no where near the correct answer, panchoman.
 
Ok so I think I get it...
Is it that the d I just solved for is the vertical distance so I need to use my angle to solve for the distance it moved down the incline?
 
The initial energy is 1/2 mv02 if you count the potential energy from the top of the slope. What is the final potential energy then?

ehild
 

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