Energy Density of a Charged Sphere?

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SUMMARY

The discussion focuses on calculating the energy density of a charged plastic sphere with a uniform charge distribution. The user initially attempted to find the fraction of total energy from the center to half the radius, concluding with a ratio of (1/8)E0. However, they recognized a critical oversight regarding the electric field's dependence on the radius, which affects energy density calculations. The user acknowledged missing essential equations that would have clarified their approach.

PREREQUISITES
  • Understanding of electric field concepts within charged spheres
  • Familiarity with energy density and its relation to volume
  • Knowledge of relevant equations in electrostatics
  • Basic calculus for integrating energy density over volume
NEXT STEPS
  • Review the derivation of electric fields inside uniformly charged spheres
  • Study energy density calculations in electrostatics
  • Learn about the implications of varying electric fields on energy distribution
  • Explore advanced topics in electrostatics, such as Gauss's Law
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Students studying electrostatics, physics educators, and anyone interested in the principles of electric fields and energy density in charged objects.

xxacefirexx
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Homework Statement



Since this was on the test, I won't be able to type out the question verbatim, but here it goes:

You have a plastic sphere with charge equally distributed through out the sphere. The radius of the sphere is a. The energy stored in the total sphere is E0 (not to be confused with electric field). Find the fraction of the total energy from r=0 to r=a/2 (half the radius).

Homework Equations



energydensity*volume = energy

The Attempt at a Solution



I simply put a ratio of the two energies, so E(small)/E0. Since charge is equally spread throughout the sphere, I figured that the energy densities would cancel out, leaving the volume(small)/volume(big). Dividing out gives (1/8)E0.

However, this seems unreasonably easy, and I think I'm missing something very important. Did I do it correctly, or am I forgetting something?
 
Physics news on Phys.org
yes it does...

so it looks like i assumed that because the charge is constant, that the electric field is constant, which is not the case.

I missed 2 big equations in that, so looks like I am not even going to get that much partial credit :frown:

at least now i can sleep knowing the answer. btw, that's an excellent site.
 

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