Electric Field of a Charged Sphere?

In summary, a sphere of radius R with total charge Q has a volume charge density that decreases linearly from ρ_0 at the center to zero at the edge of the sphere. To find ρ_0, we can use the equation ρ = Q/V and integrate the charge density to relate it to the total charge. This results in ρ_0 = 3Q/πR^3. Inside the sphere, the electric field points radially outward with magnitude E = (Qr/4πε_0 R^3) (4 - 3 r/R), and outside the sphere (r > R), the electric field can be found using the same equation.
  • #1
ronk

Homework Statement


A sphere of radius R has total charge Q. The volume charge density (C/m^3) within the sphere is ρ = ρ_0 (1 - r/R).

This charge density decreases linearly from ρ_0 at the center to zero at the edge of sphere.

a. Show that ρ_0 = 3Q/πR^3.
b. Show that the electric field inside the sphere points radially outward with magnitude E = (Qr/4πε_0 R^3) (4 - 3 r/R).
c. Find the electric field outside the sphere (r > R).

Homework Equations


Volume of a Sphere: V = 4/3 πR^3.

The Attempt at a Solution


I knew that ρ = Q/V and could make this equal to our given value of ρ to find ρ_0, but I was unable to get rid of the 4 in the denominator to find ρ_0.
 
Physics news on Phys.org
  • #2
ronk said:
I knew that ρ = Q/V
This is incorrect. The sphere does not have uniform charge. You need to integrate the charge density to relate it to the total charge.
 

1. What is an electric field of a charged sphere?

The electric field of a charged sphere is the force per unit charge exerted on a point in space around the sphere. It is a measure of the strength and direction of the electric force at any given point.

2. How is the electric field of a charged sphere calculated?

The electric field of a charged sphere can be calculated using the formula E = kQ/r^2, where E is the electric field, k is the Coulomb's constant, Q is the charge of the sphere, and r is the distance from the center of the sphere.

3. What is the direction of the electric field for a charged sphere?

The electric field for a charged sphere is directed radially outward from a positively charged sphere and radially inward for a negatively charged sphere. This means that the electric field lines point away from a positive charge and towards a negative charge.

4. How does the electric field of a charged sphere change as the distance from the center increases?

The electric field of a charged sphere decreases as the distance from the center increases. This is because the electric field strength follows an inverse square law, meaning it decreases by a factor of 1/r^2 as the distance increases.

5. Can the electric field of a charged sphere be affected by other nearby charges?

Yes, the electric field of a charged sphere can be affected by other nearby charges. The electric field at a point around the sphere will be the vector sum of the electric fields from all the charges present in the vicinity.

Similar threads

Replies
1
Views
123
  • Introductory Physics Homework Help
Replies
17
Views
384
  • Introductory Physics Homework Help
Replies
2
Views
877
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
625
  • Introductory Physics Homework Help
Replies
5
Views
792
  • Introductory Physics Homework Help
Replies
6
Views
657
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
883
Back
Top