Energy of a car going up a hill

[anthonyk2013]

find the energy of a required to accelerate a 1800kg car from 15 km/h to 75km/h an up hill road with a vertical rise of 55m

KE=1/2m(V₂²-V₁²)

KE=1/2(1800)(20.83²-4.16²)

KE=1/2(1800)(433.88-17.30)

KE=1/2(1800)(416.58)

KE=1/2(749844)

KE=374922 J

I'm wondering if I'am on the right track, no sure how to bring the rise into the problem.

 

[zoki85]

I'm wondering if I'am on the right track, no sure how to bring the rise into the problem.

+ mgh

 

[anthonyk2013]

KE=1/2m(V₂²-V₁²)+mgh ?

 

[zoki85]

Energy = Kinetic energy + Potential energy

Potential energy = mgh

 

[anthonyk2013]

Thank you