Energy of a car going up a hill

  • #1
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Not using homework template due to originally being posted in a different forum.
find the energy of a required to accelerate a 1800kg car from 15 km/h to 75km/h an up hill road with a vertical rise of 55m

KE=1/2m(V22-V12)

KE=1/2(1800)(20.832-4.162)

KE=1/2(1800)(433.88-17.30)

KE=1/2(1800)(416.58)

KE=1/2(749844)

KE=374922 J

I'm wondering if I'am on the right track, no sure how to bring the rise in to the problem.
 

Answers and Replies

  • #2
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I'm wondering if I'am on the right track, no sure how to bring the rise in to the problem.

+ mgh
 
  • #3
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KE=1/2m(V22-V12)+mgh ?
 
  • #4
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Energy = Kinetic energy + Potential energy

Potential energy = mgh
 
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  • #5
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Thank you
 

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