Energy of a photon absorbed by an elementary particle

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SUMMARY

An elementary particle of mass M absorbs a photon, resulting in a new mass of 1.01M. The energy of the incoming photon is calculated using the equation Δm = ΔE/c², leading to an initial conclusion of E = 0.01Mc². However, further analysis reveals that the correct energy is 0.01005Mc², which is greater than 0.01Mc², as required by the problem's conditions. This discrepancy highlights the importance of considering relativistic effects in photon absorption scenarios.

PREREQUISITES
  • Understanding of Einstein's mass-energy equivalence (E = mc²)
  • Familiarity with relativistic momentum (E² = (pc)² + (mc²)²)
  • Basic knowledge of elementary particle physics
  • Concept of relativistic mass and energy transformations
NEXT STEPS
  • Study the implications of relativistic mass in particle physics
  • Learn about the conservation of energy and momentum in photon absorption
  • Explore the derivation of the equation E² = (pc)² + (mc²)²
  • Investigate the role of gamma factors (γ) in relativistic equations
USEFUL FOR

Students of physics, particularly those focusing on particle physics and relativity, as well as educators looking to enhance their understanding of photon interactions with matter.

saridy
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Homework Statement


An elementary particle of mass M completely absorbs a photon, after which its mass is 1.01M.
a) What was the energy of the incoming photon?
b) Why is that energy greater than 0.01Mc2?


Homework Equations



E = mc2 or Δm = Δ E/c2
E = γmc2

The Attempt at a Solution



The only thing I can see doing is Δm = 1.01M - M = 0.01M = E/c2
But that gives E = 0.01Mc2 , which according to part b is not the answer. How do you solve this?
 
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After further reading, I'll add these equations:
(mc2)2 = E2 - (pc)2
E = pc (for m = 0)
 
OKAY. so I got an answer of 0.01005Mc^2, so I'd appreciate if someone could check/correct that for me. I still don't know how to explain it in part b.
 

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