I Energy of an electromagnetic wave

AI Thread Summary
The discussion clarifies that the energy of an electromagnetic wave is determined by its amplitude rather than frequency, contrasting this with the energy of individual photons, which does depend on frequency. It emphasizes that classical electromagnetic waves consist of many photons, and their energy can vary based on the number of photons present at a given frequency. The conversation also highlights the misconception that higher frequency light always carries more energy than lower frequency light, noting that energy density in electromagnetic waves is independent of frequency. Additionally, it points out the complexities of understanding energy in the context of classical electrodynamics versus quantum electrodynamics. The thread ultimately underscores the importance of distinguishing between the properties of photons and those of classical electromagnetic waves.
PreposterousUniverse
Messages
31
Reaction score
4
The energy of an electromagnetic wave does not depend on the frequency of the wave, only on the amplitude. Then why is light with higher frequency more energetic than light with lower frequency?
 
Physics news on Phys.org
cite ?
 
  • Like
Likes russ_watters
PreposterousUniverse said:
Then why is light with higher frequency more energetic than light with lower frequency?
I think you are confusing this with photons vs. electromagnetic waves.
 
  • Like
Likes Delta2 and vanhees71
PreposterousUniverse said:
Then why is light with higher frequency more energetic than light with lower frequency?
It isn't. A single photon has an energy that depends on frequency, yes. But by the time you've got enough photons that you can talk about light as a classical electromagnetic wave you have two variables: frequency and number of photons. You can vary the energy being carried at a given frequency by varying the number of photons. That's why classical electromagnetism has no defined relationship between energy carried and frequency.
 
  • Like
Likes Delta2 and malawi_glenn
A classical electromagnetic wave is not a photon state but a coherent state. It has not even a well-defined "photon number". Forget about photons at this stage and first study thoroughly classical electrodynamics. The energy density of the electromagnetic field in the vacuum is (in SI units)
$$u=\frac{\epsilon_0}{2} \vec{E}^2 + \frac{1}{2 \mu_0} \vec{B}^2.$$
The total energy is given by the integral over all space.
 
Then why are infrared light, visible light and microwaves less energetic than gamma rays, X-rays, and ultraviolet light?
 
PreposterousUniverse said:
Then why are infrared light, visible light and microwaves less energetic than gamma rays, X-rays, and ultraviolet light?
They aren't if you are talking about electromagnetic waves. Photons of higher frequency do have higher energy, but that's not the same thing as "all gamma radiation carries more energy than all X ray radiation", which would be wrong.
 
  • Like
Likes vanhees71
Uranium atoms are heavier than iron atoms. That does not mean that it's impossible to make a chunk of iron heavier than a chunk of uranium. The number of atoms matters as well as their individual masses!

There are complexities with photons that aren't present in this analogy, to which @vanhees71 alludes. But the basic problem is that you are taking statements that are true about individual photons and assuming that they apply to arbitrary EM waves that are not single photons.
 
  • Like
Likes malawi_glenn and vanhees71
In free space, the energy density of an EM wave moving in the z direction has a time dependent amplitude that can be given by

1659548930557.png

If you average over one period Save becomes

1659548945616.png


This is independent of frequency but allows the energy of the wave to contain or be composed of a number of individual quanta whose energy does depend on the frequency ( hf)

1659548959147.png
 
  • #10
Sigh. Why is everybody so obsessed in using a kind of pseudo-photons in classical electrodynamics? A classical electromagnetic wave is, seen from the QED perspective, a coherent state of the electromagnetic (quantum) field. For not too low intensities the quantum fluctuations can be neglected and you can work with classical electrodynamics.
 
  • Like
Likes weirdoguy, malawi_glenn and Lord Jestocost
  • #11
@vanhees71 Sigh. Sorry about that, I figured I might get a negative reaction. However, the OP suggested that he/she might not be able to look at a classical EM wave from a QED perspective.
 
  • #12
PreposterousUniverse said:
Then why are infrared light, visible light and microwaves less energetic than gamma rays, X-rays, and ultraviolet light?

Are they? My microwave oven is 800 W. My gamma ray emitting samples in the physics lab does not come close to that (would be kinda disasterous if they did)

Radiowave transmitters also have some substantial power
 
  • Like
Likes Vanadium 50, Nugatory, vanhees71 and 1 other person
  • #13
Comparing energy and power?
 
  • #14
gleem said:
Comparing energy and power?
How do you measure energy in a wave? How can I have just one single radio wave?

If OP @PreposterousUniverse could mention the sources for his claims, I think we can help him/her better
 
Last edited:
  • Like
Likes vanhees71
  • #15
I am really confused. Two years ago, the OP ws discussing gauge transformation. Now he seems to be mixing together classical EM, classical waves, photons, wavelength, frequency, energy and power. What is going on?
 
  • Like
Likes vanhees71
  • #16
Some retardation effect? ;-) SCNR.
 
  • Like
Likes gleem
Back
Top