Energy of Motion: 2.4kg-mass w/ 7.0cm amp & 5.0Hz freq

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Homework Help Overview

The discussion revolves around a physics problem involving a 2.4 kg mass attached to a spring, oscillating with a specified amplitude of 7.0 cm and a frequency of 5.0 Hz. Participants are exploring how to calculate the energy of motion associated with this system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss relevant energy equations, including those for potential energy in springs and kinetic energy. There is an attempt to clarify the use of variables, particularly the distinction between amplitude and extension in the context of the spring's energy. Some participants express confusion about their calculations and seek guidance on the correct approach.

Discussion Status

There is ongoing exploration of the problem with various approaches being discussed. Some participants have provided equations and attempted calculations, while others are questioning the correctness of their results. No consensus has been reached, but there is a productive exchange of ideas and clarifications regarding the concepts involved.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the type of assistance they can receive. There is an emphasis on understanding the relationships between different forms of energy in the oscillating system.

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Homework Statement


A 2.4kg- mass attached to a spring oscillates with an amplitude of 7.0cm and a frequency of 5.0Hz .
What is its energy of motion?
Express your answer using two significant figures.
in J.

Homework Equations





The Attempt at a Solution

 
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people are going to ask you to give it a shot be for they help. Let's start with what equations should you use>
 
You have two energy formulas that apply:
E = 1/2*k*x^2 for when the spring is stretched but the bob is not moving.
E = 1/2*m*v^2 when the object is moving but the spring is not stretched.
Looks like the first one will be easier to work out!
 
ok i have my T which is 0.2s
omega is 31.4
k is 2366.3
and amplitude is 7
eqn to be used is E=1\2kA(squared) i believe but i cannot get the correct answer doing so
 
I haven't seen E = 1/2*k*x^2 written with an A instead of an x.
The x means "extension" or how much the spring is stretched.
Or compressed.
That just means the 7 cm, I think.

As the spring oscillates, this energy is repeatedly converted back and forth between spring energy and kinetic energy. If you knew the maximum speed of the bob, you could use E = 1/2mv^2 and get the same answer. Or you could set 1/2*k*x^2 at maximum extension equal to 1/2mv^2 at maximum speed and solve for the speed.
 
i see, i still cannot get the right answer i don't no what I am doing wrong
 
my answers come to 580 or 5.8*10^5
and it comes up wrong
 

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