Energy required to expand V of cylinder

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SUMMARY

The work done when the volume of a cylinder is increased by 90.0 L against atmospheric pressure is calculated to be 9,117 Joules (J). The conversion from liters to cubic meters is essential, where 90.0 L equals 0.0900 m³. The pressure used in the calculation is 1.013 x 10^5 Pascals (Pa), which is equivalent to 1.013 x 10^5 Newtons per square meter (N/m²). The final result confirms the accuracy of the calculation using unit analysis.

PREREQUISITES
  • Understanding of unit conversions, specifically from liters to cubic meters.
  • Basic knowledge of pressure units, particularly Pascals (Pa).
  • Familiarity with the concept of work in physics, defined as force multiplied by distance.
  • Ability to perform calculations involving pressure and volume in thermodynamics.
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  • Study the principles of thermodynamics, focusing on work done by gases.
  • Learn about the Ideal Gas Law and its applications in calculating work.
  • Explore the concept of pressure-volume work in isothermal and adiabatic processes.
  • Investigate the relationship between work, energy, and heat transfer in thermodynamic systems.
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AP Chemistry students, physics students, and anyone interested in understanding the calculations related to work done in thermodynamic processes involving gases.

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Homework Statement



Calculate the work done when the volume of a cylinder is increased by 90.0 L against the atmospheric pressure. Think about the upward movement of a piston as it expands the volume of a cylinder.

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I am actually an AP Chemistry student and am supposed to do this problem using unit analysis as I am not taking AP Physics. However, I have taken Grade 11 Physics.

Thank you for your help!

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My Work:

Since 1 L = 0.001 m3, then 90.0 L = 0.0900 m3.

Since 1 Pa = 1 N/m2, then 1.013E5 Pa = 1.013E5 N/m2.

In order to get Nm = J = work:

1.013E5 N/m2 x 0.0900 m3 = 9,117 Nm = 9117 J = 9.12 x 103 J.
 
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That looks correct.
 
Thank you for your response!
 

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