Energy stored in a capacitor graph

Click For Summary
SUMMARY

The discussion centers on the graphical representation of energy stored in a capacitor during charging and discharging phases. The energy stored in a capacitor can be calculated using the formula E = 0.5QV, where Q is the charge and V is the voltage. For charging, the voltage over time follows the equation V*(1-e^(-t/RC)), where RC represents the time constant. The graph of energy versus time during charging exhibits a similar shape to the voltage versus time graph, while the discharging phase demonstrates exponential decay.

PREREQUISITES
  • Understanding of capacitor charging and discharging principles
  • Familiarity with the formula E = 0.5QV for energy calculation
  • Knowledge of the time constant (RC) in RC circuits
  • Basic grasp of exponential functions and their graphs
NEXT STEPS
  • Study the derivation of the charging voltage equation V*(1-e^(-t/RC))
  • Explore the graphical representation of exponential decay in discharging capacitors
  • Learn about the implications of time constants in RC circuits
  • Investigate the relationship between charge, voltage, and energy in capacitors
USEFUL FOR

Electrical engineers, physics students, and anyone interested in understanding capacitor behavior in circuits will benefit from this discussion.

nokia8650
Messages
216
Reaction score
0
What would a graph of Energy stored in a capacitor whilst charging and discharging a capacitor against time look like?

Would the graph of Energy stored vs. time whilst charging have the same shape as the Voltage/time graph?

For discharging, would it be exponential decay?

Thanks
 
Physics news on Phys.org
It seems to me you'll need a formula for energy versus voltage and capacitance. I wonder where you could find that.
 
Thanks for the reply. E=0.5QV. This doesn't relate the energy to time, however.

Thanks
 
For a charging capacitor the formula is V*(1-e^-(t/rc)) where V is the supply voltage used for charging, e is the number e, about 2.71, t is the charging time and rc is the charging resistance times the capacitance. RC is often called the time constant or tau.

For instance if R=1k ohm and C=1 uF, the time constant would be 1k * 1u or .001 seconds. This means that if you charged that capacitor for 1 millisecond it would be 1-e^-(.001/.001) or 1 - e^-1 or about 63.2% charged. Multiply that by the charging voltage to get the charged voltage.
 
Thanks a lot for the reply. So what would graphs of ENERGY vs. time look like? I am aware of the case for Voltage, charge and current.

Thanks
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
20
Views
2K
Replies
43
Views
3K
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 9 ·
Replies
9
Views
580
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K