Energy stored in a capacitor graph

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Homework Help Overview

The discussion revolves around the graphical representation of energy stored in a capacitor during charging and discharging phases, specifically how it relates to time. Participants are exploring the characteristics of these graphs and their shapes in relation to voltage and time.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the relationship between energy stored in a capacitor and time, particularly whether the graph of energy during charging resembles the voltage versus time graph. There is also curiosity about the nature of the graph during discharging, with suggestions of exponential decay.

Discussion Status

Some participants have provided formulas related to energy and voltage, while others are seeking clarification on how these relate to time. There is an ongoing exploration of the shapes of the graphs for energy versus time, indicating a productive discussion without a clear consensus yet.

Contextual Notes

Participants are working within the constraints of understanding the mathematical relationships involved, and there is an acknowledgment that the energy formula does not directly relate to time without further context.

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What would a graph of Energy stored in a capacitor whilst charging and discharging a capacitor against time look like?

Would the graph of Energy stored vs. time whilst charging have the same shape as the Voltage/time graph?

For discharging, would it be exponential decay?

Thanks
 
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It seems to me you'll need a formula for energy versus voltage and capacitance. I wonder where you could find that.
 
Thanks for the reply. E=0.5QV. This doesn't relate the energy to time, however.

Thanks
 
For a charging capacitor the formula is V*(1-e^-(t/rc)) where V is the supply voltage used for charging, e is the number e, about 2.71, t is the charging time and rc is the charging resistance times the capacitance. RC is often called the time constant or tau.

For instance if R=1k ohm and C=1 uF, the time constant would be 1k * 1u or .001 seconds. This means that if you charged that capacitor for 1 millisecond it would be 1-e^-(.001/.001) or 1 - e^-1 or about 63.2% charged. Multiply that by the charging voltage to get the charged voltage.
 
Thanks a lot for the reply. So what would graphs of ENERGY vs. time look like? I am aware of the case for Voltage, charge and current.

Thanks
 

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