Energy stored in the steady state circuit

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Homework Help Overview

The discussion revolves around a circuit problem involving energy storage in a steady state circuit, specifically focusing on the behavior of voltage and current as time approaches infinity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to confirm their calculation of energy stored in the circuit, which they initially state as 4.4J. Participants inquire about the approach used to arrive at this result and suggest showing the work involved.

Discussion Status

Some participants have provided guidance on applying Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) to the problem. There is acknowledgment of the need to simplify the circuit by recognizing steady state conditions, but there is also a correction regarding a miscalculation in the energy formula, indicating an ongoing exploration of the problem.

Contextual Notes

There is mention of a potential miscalculation related to the units of energy, with a suggestion that the correct value should be in nanojoules (nJ) rather than joules (J).

hoangpham4696
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TL;DR Summary: Hi everyone. I have this circuit problem. I know that vL=0 and iL is just a constant number at t-> infiniti. I have attempted this problem and got energy stored = 4.4J. Please confirm it with me if my approach to the problem is correct. Thank you all.

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Welcome to PF.

hoangpham4696 said:
Please confirm it with me if my approach to the problem is correct.
What approach? Please show the work you used to come to that result. Thank you.
 
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Here is my approach
IMG_0399.JPG
 
Yes! A good cookbook application of KVL & KCL.
Later, you will learn to do this much more quickly by reducing the complexity of the network with some observations. For example, as you said for steady state ##v_l=v_b=0##, so you can replace both of those with a short circuit. That voltage will be zero regardless of the current flow.
 
DaveE said:
Yes! A good cookbook application of KVL & KCL.
Later, you will learn to do this much more quickly by reducing the complexity of the network with some observations. For example, as you said for steady state ##v_l=v_b=0##, so you can replace both of those with a short circuit. That voltage will be zero regardless of the current flow.
Thank you so much. I appreciate you checking it for me.
 
hoangpham4696 said:
Thank you so much. I appreciate you checking it for me.
Oops! I didn't check the final result. You miscalculated ##0.5 LI^2##. You're off by powers of 10. Try that again.
 
DaveE said:
Oops! I didn't check the final result. You miscalculated ##0.5 LI^2##. You're off by powers of 10. Try that again.
Ok I see. It should be in nJ. So 4.37 nJ. Thank you
 
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hoangpham4696 said:
Ok I see. It should be in nJ. So 4.37 nJ. Thank you
Yep. Good work!
 
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