Energy to raise temperature of water

Click For Summary

Homework Help Overview

The discussion revolves around a problem in thermodynamics concerning the mixing of water at different temperatures to achieve a desired final temperature. The original poster attempts to calculate the mass of boiling water needed to raise the temperature of a pot of water from 40.0 °C to 65.0 °C.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the setup of the problem, including the mass and temperature of the water involved. There are attempts to clarify the calculations and units used in the equations. Some participants question the accuracy of the original calculations and suggest corrections.

Discussion Status

There is ongoing dialogue regarding the calculations, with some participants providing corrections and others verifying the results. The discussion includes checking the units used in the calculations and addressing potential overflow issues with the water quantities involved.

Contextual Notes

Participants note the importance of accurate unit representation and the implications of the calculated mass of water in relation to the capacity of the pot being used.

Dazed
Messages
26
Reaction score
0
Just looking for someone to check my work on this question before I submit it to the teacher. Any help is appreciated. :)

3. A 0.500 kg pot of hot water for tea has cooled to 40.0 OC. How much freshly boiled water must be added (at 100 OC) to raise the temperature of the tea water to a respectable 65.0 OC?

Let n represent the unknown mass of water to be added.

Starting water + Added water = total water

40c x 0.5 kg + 100c x n = 65 (0.5kg + n)

20 kg + 100 n = (32.5kg + 65n)

52.5 kg = 165 n

1 kg = 3.1n

n = 1/3.1

n = 0.32 kg

To raise the temperature of the tea to 65 degrees, 0.32kg of 100c water must be added.


~Dazed
 
Physics news on Phys.org
No, you messed up the third step. Subtract 65n from both sides, and 20 kg, to get
35n = 12.5kg
You can finish it from there.

A small additional note: your units aren't complete, when you multiply temperature times mass, the units are c-kg. Won't matter in the end, but keeping accurate track is a good habit.
 
Thank you for your reply. :)

I think I've correctly fixed this as per your suggestions, I used the units c/kg instead of c-kg, I assumed that was a typo. If c-kg is correct please tell me and I'll change it. Also please tell me if the new answer is correct or of I messed up somewhere again. :)

3. A 0.500 kg pot of hot water for tea has cooled to 40.0 OC. How much freshly boiled water must be added (at 100 OC) to raise the temperature of the tea water to a respectable 65.0 OC?

Let n represent the unknown mass of water to be added.

Starting water + Added water = Total water

(40c x 0.5 kg) + (100c * n) = 65c(0.5kg + n)

20c/kg + 100n = (32.5c/kg + 65n)

Subtract 65n from both sides
20c/kg + (100n - 65n) = 32.5c/kg + (65n – 65n)

20c/kg + 35n = 32.5c/kg

Subtract 20kg from both sides
(20kg – 20kg) + 35n = (32.5kg – 20kg)

35n = 12.5kg

n = 12.5kg / 35

n = 0.357kg

To raise the temperature of the tea to 65 degrees, 0.357kg of 100c water must be added.
 
Correct answer. You're units are still a little confused. If you multiply 40c x 0.5 kg, you get 20 c kg (whatever that is!). Then when you get down to
35c * n = 12.5 c kg
and solve, you get
n =12.5 c kg / 35 c
and the answer has units of kg as you knew it must.
 
NO. If you added 0.357kg of water to the pot it would overflow. You would have to add both parts of the water to a 0.900 kg pot and then return 0.500 kg to the original pot.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
5
Views
6K
Replies
1
Views
4K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K