Calculating Time for Immersion Heater to Raise Water Temperature

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Homework Help Overview

The discussion revolves around calculating the time required for an immersion heater rated at 9 kW to raise the temperature of 40 gallons (approximately 150 liters) of water from 15°C to 40°C. The participants are exploring the application of the heat transfer equation and the relationship between power, heat energy, and time.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the equation Q = C * m * deltaT to calculate the heat energy required. There are questions about the correct manipulation of the power equation P = ΔQ / Δt to find time. Some participants express confusion regarding algebraic rearrangements and the steps needed to solve for time.

Discussion Status

There is ongoing dialogue about the correct approach to rearranging equations and applying values to find the time. Some participants have provided guidance on algebraic manipulation, while others express uncertainty about the calculations and seek additional resources for learning.

Contextual Notes

Participants mention challenges with algebraic skills and the complexity of solving for variables. There is a reference to the need for tutorials or textbooks to aid understanding.

physicskillsme
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Extracted from another thread tha had got a bit messy.

The immersion heater in an electric hot water system is rated at 9 kW. If the tank is initially filled with 40 gallons (about 150 litres, with a mass of 150 kg) of cold water at 15 oC, how long will it take the heater to raise the temperature to 40 oC?

Ok this is as far as I have got:

Q=CmdeltaT

deltaT=40-15 = 25

q=Q=4196*150*25

15735000J

Ok so now I need to get time.

p=deltaq/deltat

So to get time do I just say time=p*delta q ?
 
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physicskillsme said:
So to get time do I just say time=p*delta q ?

Almost but not quite, i think you algerbraic skills are letting you down;

P = \frac{\Delta Q}{\Delta t}

P\Delta t = \Delta Q

\Delta t = \frac{\Delta Q}{P}

Your theory is right, just the manipulation. A quick check to see if your manipulation is right is to take a look at the units.

-Hoot:smile:
 
Hootenanny said:
Almost but not quite, i think you algerbraic skills are letting you down;

P = \frac{\Delta Q}{\Delta t}

P\Delta t = \Delta Q

\Delta t = \frac{\Delta Q}{P}

Your theory is right, just the manipulation. A quick check to see if your manipulation is right is to take a look at the units.

-Hoot:smile:

So I need to do the calcualtions for each of these steps?

Yes I am having problems with solving for variables it just seems so complicated. Do you know of any good tutorials for this?
 
physicskillsme said:
So I need to do the calcualtions for each of these steps?

No, all you have done is re-arranged an equation, you can just plug your numbers in for P and \Delta Q(which you have calculated earlier).

physicskillsme said:
Do you know of any good tutorials for this?

I'm afraid I don't, but a quick internet search would probably show up a few. If you can get hold of a high school mathematics textbook, that would probably be best.

-Hoot:smile:
 
So this the solution?

The immersion heater in an electric hot water system is rated at 9 kW. If the tank is initially filled with 40 gallons (about 150 litres, with a mass of 150 kg) of cold water at 15 oC, how long will it take the heater to raise the temperature to 40 oC?

Q=CmdeltaT

deltaT=40-15 = 25

Q=4196*150*25

15735000J

delta t= delta q/p

1748.33 =15735000/9000

1748 seconds
 
Yep, that looks right to me

-Hoot:smile:
 

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