Energy: work with an inclination problem

In summary, the escalator did work on Karen as she rode it up. The escalator has an inclination of 34 degrees, so the work done was 34.8 J.
  • #1
Brt346
3
0
1. Karen has a mass of 52.9 kg as she rides
the up escalator at Woodley Park Station of
the Washington D.C. Metro. Karen rode a
distance of 62.3 m, the longest escalator in
the free world.
The acceleration of gravity is 9.8 m/s^2 :
How much work did the escalator do on
Karen if it has an inclination of 34 degrees? Answer
in units of J.


Homework Equations





3. The Attempt at a Solution i got the height to equal 34.83771789. i don't know if that helps or is needed.
 
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  • #2
Ok. Now, you have the height. Whenever, a body is at a height, it has some 'Gravitational Potential Energy'. What is this energy in this case?
 
  • #3
does it have kinetic energy? be/c it doesn't say that she starts out at rest.
 
  • #4
i really don't know. i am very lost and frustrated.
 
  • #5
Whenever, a body is at a height, it has some 'Gravitational Potential Energy'. This is calculated as: [itex]E = mgh[/itex]. Where, 'm' is the mass of the object, 'g' is the acceleration due to gravity and 'h' is the height from the reference point (or level). When the body falls from this height to the reference level, it has the same energy the GPE. It is however converted to Kinetic Energy.

The reference point is the point/level where you assume the potential energy to be zero. Here, the height 'h' is taken to be zero. We do this because, we can't really calculate potential energy (in classical mechanics atleast). We can only calculate the change in the potential energy when the body is moved somewhere.

Here, take the ground as h = 0. Here we take the GPE as 0. After her height is increased by 'h', her GPE increases. By conservation of energy, it follows that this energy was supplied by the escalator, which we term as 'work' done by the escalator. So calculate this energy using the formula i have earlier.

if u still have any doubts.. feel free to post.
 

1. What is an inclination problem in terms of energy and work?

An inclination problem in energy and work refers to a situation where an object or system is moving along a surface that is not horizontal. This creates an angle between the direction of motion and the force of gravity, which affects the amount of work that needs to be done to move the object or system.

2. How does the angle of inclination affect the amount of work required?

The greater the angle of inclination, the more work is required to move an object or system. This is because the force of gravity acting on the object is no longer perpendicular to the direction of motion, so more energy is needed to overcome this force and move the object along the inclined surface.

3. What is the formula for calculating work in an inclination problem?

The formula for work in an inclination problem is W = Fdcosθ, where W is work (measured in joules), F is the applied force (measured in newtons), d is the distance moved in the direction of the force (measured in meters), and θ is the angle of inclination (measured in degrees).

4. How does energy conservation apply to an inclination problem?

In an inclination problem, energy is conserved meaning that the total amount of energy in the system remains constant. This means that the work done to overcome the force of gravity is equal to the change in potential energy of the object or system, as well as any other forms of energy involved.

5. What are some real-life examples of inclination problems in energy and work?

Examples of inclination problems in energy and work include pushing a loaded shopping cart up a ramp, hiking up a steep slope, or lifting a heavy object up a flight of stairs. In each of these examples, the angle of inclination affects the amount of work needed to move the object or system, making it more difficult to do so.

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