I Entanglement, Mixed or Pure State?

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When two particles are entangled, the overall state describing both particles is a pure state, while the individual states of each particle are mixed states represented by a density operator. The singlet state of two spins exemplifies this, as it is a pure entangled state with a wavefunction, yet when measuring one particle alone, the state appears mixed. This distinction clarifies that not all entangled states are mixed; rather, the entanglement leads to a pure state for the system as a whole. The confusion arises from the different contexts in which mixed and pure states are discussed. Understanding this relationship is crucial for grasping quantum entanglement.
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I have a source that says when two particles are entangled, we must describe them using the density operator because it is a mixed state. But I have another source that says that the singlet state of two spins is an entangled state, but that has a wavefunction. So could someone explain what I am misunderstanding? Are all entangled states mixed states or only some?
 
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Would be helpful if you clarified what your sources are.
 
stephen8686 said:
when two particles are entangled, we must describe them using the density operator because it is a mixed state.
When two particles are entangled the state of either one is a mixed state that can only be described with a density operator. (in the most convenient basis the density matrix for either particle is ##diag(1/2,1/2)##, equal probability of measuring spin-up or spin down).
But I have another source that says that the singlet state of two spins is an entangled state, but that has a wavefunction.
The singlet state is the state of a single quantum system that will produce measurement results at two spatially separated detectors. It is a pure state with a wave function - but it is not the state of either particle considered in isolation.
 
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stephen8686 said:
I have a source that says when two particles are entangled, we must describe them using the density operator because it is a mixed state. But I have another source that says that the singlet state of two spins is an entangled state, but that has a wavefunction. So could someone explain what I am misunderstanding? Are all entangled states mixed states or only some?
To rephrase what @Nugatory said, the state that simultaneously describes both particles together is pure, while the state that describes any of the particles alone is mixed.
 
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For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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