Enthalpy Question: H2 (g) + Cl2 (g) --> 2 HCl (g) + 184.62 kJ

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SUMMARY

The reaction H2 (g) + Cl2 (g) --> 2 HCl (g) releases 184.62 kJ of energy, indicating an exothermic process. The correct statements regarding the enthalpy changes are that the enthalpy of the reactants is greater than that of the products, and the change in enthalpy (ΔH) is negative, specifically -184.62 kJ. The initial analysis incorrectly identified the enthalpy relationship, but the answer key confirms that statements 1 and 4 are accurate.

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Homework Statement



H2 (g) + Cl2 (g) --> 2 HCl (g) + 184.62 kJ

Four statements about energy changes in reactions are listed below:

1. The enthalpy of the reactants is greater than the enthalpy of the products.
2. The enthalpy of the reactants is less than the enthalpy of the products.
3. The change in enthalpy of this reaction is positive.
4. The change in enthalpy of this reaction is negative.

Which two statements are true for this reaction?

2.The attempt at a solution

The delta H is -186.62 kJ; therefore the enthalpy of the products must be greater than the enthalpy of the reactants. I chose statement 2 & 4.

The answer key states that statements 1 & 4 are correct.
 
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ThatDude said:

Homework Statement



H2 (g) + Cl2 (g) --> 2 HCl (g) + 184.62 kJ

Four statements about energy changes in reactions are listed below:

1. The enthalpy of the reactants is greater than the enthalpy of the products.
2. The enthalpy of the reactants is less than the enthalpy of the products.
3. The change in enthalpy of this reaction is positive.
4. The change in enthalpy of this reaction is negative.

Which two statements are true for this reaction?

2.The attempt at a solution

The delta H is -186.62 kJ; therefore the enthalpy of the products must be greater than the enthalpy of the reactants. I chose statement 2 & 4.

The answer key states that statements 1 & 4 are correct.
ΔH=Hproducts-Hreactants=-184.62 kJ

Chet
 

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