Entropy of Reeh-Schlieder correlations

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SUMMARY

The discussion centers on the Reeh-Schlieder theorem in Algebraic Quantum Field Theory (AQFT), which states that any analytic state in energy exhibits non-local correlations. It is established that reducing the distance between wedges increases entanglement, reaching a maximum for tangent wedges, where all analytic states become maximally entangled. The conversation also addresses whether maximal entanglement results in infinite entanglement entropy, concluding that while vacuum states exhibit UV-divergent entropy, not all maximally entangled states necessarily share infinite entropy.

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arpharazon
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Any state analytic in energy (which includes most physical states since they have bounded energy) contains non-local correlations described by the Reeh-Schlieder theorem in AQFT. It is further shown that decreasing the distance between wedges will increase the entanglement as measured by a Bell-type inequality, until it reaches a maximum for tangent wedges. In this situation all analytic states are maximally entangled.

Does maximal entanglement translate into infinite entropy of entanglement?

My intuition is based on the fact that the vacuum state (which is analytic hence subject to RS correlations) follows a UV-divergent area law or a UV-divergent log law for entanglement entropy, depending on the dimension, criticality or the bosonic/fermionic character of the field, but anyway, entropy diverges. Vacuum being maximally entangled, it means that all maximally entangled states have the same entropy of entanglement i.e. infinite entropy.

Correct me if I am wrong.
 
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Typically the entanglement entropy has a finite limit despite what you might naively think from area/length laws. For a simple 1+1D worked example see:
https://arxiv.org/abs/hep-th/0405152
 

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