alfredblase
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thanks ttn, I also added more questions afterwards, sorry I tend to post and keep retouching them until I'm happy.
alfredblase said:Leandros,
if anyone else can make sense of your objections and put them forward in a clear manner I shall try and answer them. I'm sorry but I do not have a clue what you are talking about.
alfredblase said:oh and concerning my experiment, what do you consider region 1 to be? region 2? and region 3?
what is considered a "full specification"?
alfredblase said:you havn't specified region 3 :P =)
An example he gives somewhere: in Maxwellian electrodynamics, the E and B fields (and functionals of them) are beables, while the potentials V and A are not. That is why nobody thinks locality is violated when, in Coulomb gauge, the potential V at some point changes instantaneously when a distant charge is moved. By contrast, if the fields E or B were to change instantaneously, that *would* be a problematic kind of nonlocality since those fields are supposed to represent "beables".
alfredblase said:QM tells us that spin is a non-commuting observable. This tells us that until we measure the spin of one of the entangled electrons, in a particular direction, we are violating local realism.
Meaning that we are violating the assumption that all properties are defined in reality as being something in particular (up or down in this case), even if a particular properety has never been measured.
well anyway we need not concern ourselves with balls because there is no QM wavefunction defining the colour of billiard sized balls, and so since we are performing this experiment to test the validity of QM we need not discuss balls.
alfredblase said:ok so a beable is a description of a variable that does not need a field from a source different to its own in order to be defined. do you agree?
and from their appearance, you conclude about a non-locality.
alfredblase said:hmmm so all wavefunctions in QM are beables?
alfredblase said:I have at no point talked about locality in any of my arguments. What is your definition of locality please?
alfredblase said:this is what i suspected. It seems that beable is not a clearly and well defined word...
And that therefore neither is Bell Locality. Indeed I have read this elsewhere; I have even read that no physical significance is attached to Bell Locality...
So it seems you cannot definitely and inequivocably (not sure if i spelt that right :P, I am a bit tipsy at the mo :P ) define what you mean by locality. Therefore I will not consider that any post so far has demonstrated that QM doesn't violate something that really shouldn't be violated.
vanesch said:Bell locality is a clear concept, because it deals with OUTCOMES of experiment (or the empirical predictions of the outcomes of experiment of a physical theory). As such, quantum theory, and all other theories that are empirically equivalent to it, are Bell-non-local. They violate the conditions which define Bell locality. Bell locality is independent of any interpretation of the formalism, because it deals only with experimental outcomes.
Even without any theory, a list of observations can be judged to be Bell local or not.
vanesch said:Now, if your ontology has to have any sense what so ever, then SIGNALS should have some or other beable status. So a theory that does not satisfy SIGNAL LOCALITY will have a hard time having "beable"-locality. Signal non-locality leads to paradoxes in relativity.
Signal locality is ANOTHER condition on experimental outcomes (less severe than Bell locality). Quantum theory (and empirically equivalent theories) are signal-local (that was my proof with the reduced density matrix).
As such, the gate is still OPEN for (beable) locality.
I think I said something like that you can infer that quantum theory and nature are nonlocal depending on how you interpret the theory.alfredblase said:sherlock you also refer to locality as being the violated principle. Is your definition of locality that given by Bell Locality or do you use another one? If another please give this definition.
The only thing that the theory is asserting unambiguously about reality is the calculation of probability distributions of instrumental output. That's what it does, that's what it's for. It's a theory about quantum phenomena. Quantum phenomena are instrumental phenomena. Even if that's all the formalism is about, it's nevertheless telling us *something* about the way the world works.ttn said:One way of reading orthodox QM is to take wave functions as beables. If we do that, the theory violates Bell Locality. On the other hand, if we don't do that -- and hence say that the theory has no beables at all, then the question of the theory's locality becomes meaningless because, really, it isn't even a theory unless it asserts *something* about the way the world works.
ttn said:vanesch, perhaps you are also tipsy? This is completely wrong.
Bell Locality does not pertain exclusively to experimental outcomes. It is a statement about the probabilities for such outcomes *as assigned by some particular theory*. You *can't* just look at some outcomes and say yes/no Bell Locality was/wasn't violated.
alfredblase said:But you must understand that an interpratation that does not violate causality is essential to QM, and that it must be found before we can accept QM as a a physical theory.
ttn said:The reason I wonder is that, according to MWI, all of the other "people" in the universe are actually mindless hulks. So if I transmit a signal to them, it is never really consciously received, i.e., it wasn't really a signal.
vanesch said:I thought that Bell locality came down to requiring that all observed (or empirically predicted) correlations respected all thinkable Bell inequalities.
Your theory 1 is a theory that is Bell local, but is not beable local (and as such a very strange theory!), that is, the outcomes do not violate the Bell inequalities (and hence CAN be generated by a theory that is, according to your wordings, Bell local). However, the inner gears and workings of the theory do involve non-local actions, but which are such, that this compensates entirely any potential signal or Bell non-locality (my definition).
If Bell locality were a property of a theoretical construction, one could not test it in a lab! I think you're mixing up Bell locality and "beable locality". (and then, it is maybe just a matter of semantics, but I prefer to keep Bell locality for that typical requirement of respecting Bell inequalities, something that is entirely independent of any theory behind it).
alfredblase said:you forgot to quote my first sentence vanesch...
"a theory must be testable on all counts"
since MWI predicts many worlds and since these many worlds can never be observed, MWQM is not a physical theory either.
ttn said:So it wouldn't even make sense to say something like "OQM is nonlocal because it violates a Bell inequality." It does violate the inequality, yes, but that doesn't prove squat about whether it's local or not, because it isn't the kind of theory (namely, the kind of hidden variable theory) to which the inequalities are supposed to apply.
) it would then be silly to say that the theory is not "Bell local" according to this definition.Well maybe we're just using words differently. I have no idea what you mean by "beable local." But what *I* mean by "Bell Local" is what Bell meant, as explained in several of his papers and in the paper I mentioned above.
And my theory1 from that previous post is definitely not Bell Local -- even though, as you point out, the theory doesn't predict any violation of bell inequalities.
Your talk of the "inner gears and workings" is more along the lines of what I (and Bell) mean by Bell Locality.
By the way, my toy theory1 is, in all relevant respects, exactly like orthodox QM. Theory1 and OQM violate Bell Locality for exactly the same reasons (and are signal local for exactly the same reasons too).
Can you define "beable locality"?
BTW, you're absolutely right that you can't *directly* test Bell Locality in a lab. That's why Bell's two part argument is so important. The first part shows that the only way to Bell-Locally explain a certain set of the observed correlations is for certain kinds of hidden variables to exist. Then the second part (the derivation of the inequality) shows that that kind of hidden variable theory can't account for some of the other observed correlations. So it's only at the end of that whole chain of reasoning that one is entitled to conclude that Bell Locality fails (in the sense that no Bell Local theory can be consistent with the observed facts).
vanesch said:Right. In the Copenhagen view, where the wavefunction does not represent any physical quantity (where it is even left open as to whether nature exists on the microscopic level) it would then be silly to say that the theory is not "Bell local" according to this definition.
The essence of Bell's work is, I'd say, the derivation of his inequalities, and the particularity of quantum theory is that it violates _IN ITS PREDICTIONS OF OBSERVABLE MEASUREMENTS_ these inequalities. So I'd say that THIS property is what captures most what Bell meant with his concept of "locality".
ttn said:But he (and generations of followers) also insisted that the wave function alone provides a *complete* description of... [something]. I can only assume that something is the relevant aspect of the quantum world.
selfAdjoint said:No in Copenhagen it's a complete description of anything we might find if we did an experiment. So it's not ontological, at least in the traditional sense, but kind of meta-epistomological. It's not "knowledge" exactly, because it's complete, and knowledge for Bohr can only be knowledge of the familiar macroworld; it's the prior necessity for knowledge.
If this sounds like pop Kant, you're right. All that generation of German-influenced physicists studied Kant as teenagers; this was the peak of the German educational tradition, before the deluge. It informed their thinking.
Now, specifically, what you say in the first sentence doesn't make sense. The wave function in QM is *not* a description of measurement outcomes. It just isn't. That isn't the role it plays in the theory. Rather, you *use* the wave function to compute the possible measurement outcomes. So a statement like "the wave function is a complete description of possible measurement outcomes (or their probabilities or whatever)" is incoherent. Or, if coherent, it has nothing to do with how orthodox QM actually works as a theory. So I'm unwilling to accept that position as what Copenhagen really means.