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Equality in binary choices

  1. Feb 12, 2014 #1
    Suppose we have 2n binary choices. Then the probability of having the same number of results is :

    C(2n,n)/2^(2n) ?

    I don't know if this is true, since for the case n=1million, we have a probability as high as 1/2000, which seems quite important ?
  2. jcsd
  3. Feb 12, 2014 #2


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    Your estimate seems about right. What is that a concern?
  4. Feb 13, 2014 #3
    this was about votations : if we suppose 2 million 1 people vote a law then the highest probability is that only 1 voice makes the difference. I heard some people intepret this as there exist a sort of hidden dictator, but in fact we dont know who made the balance choice.
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