Equation for displacement in damped harmonic motion.

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SUMMARY

The equation for displacement in damped harmonic motion is given by x=Cexp(-b/2mt)·exp(±√(b²/2m-k/m)t). In this equation, C is a constant determined by the initial conditions of the system. To find the value of C, one typically uses the initial displacement x₀ at time t=0. By substituting these values into the equation, you can solve for C, which acts as a constant of integration in the context of the motion.

PREREQUISITES
  • Understanding of damped harmonic motion
  • Familiarity with the concepts of initial conditions in physics
  • Knowledge of exponential functions and their properties
  • Basic skills in solving algebraic equations
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  • Learn about the physical significance of the damping coefficient b
  • Explore the role of initial conditions in determining motion parameters
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the principles of damped harmonic motion.

Craptola
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This is not really a homework problem but rather a question about an equation for displacement in damped harmonic oscillations that I've come across during revision for midterms. In my notes and in various textbooks the equation is given as x=C\mathrm{exp}(-\frac{b}{2m}t)\cdot\mathrm{exp}(\pm \sqrt{\frac{b^{2}}{2m}-\frac{k}{m}}t)

I've been told that C is a constant depending on the initial conditions of the system, but I'm not sure how to go about determining the value of this constant.
Any help on this matter would be greatly appreciated.
 
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You use a value for x that you know for some value of t. Usually ##t=0## and ##x=x_0## - you know, how far you pulled the pendulum back before you let it go?
You put the numbers into the equation and solve for C. It's a constant of integration.
 

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