(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An ordinary 150-Watt light bulb has a resistance of about 96 ohms.

Suppose you were to connect a 2.0 V battery to such a light bulb. How much current would flow? Determine how much power the bulb would radiate? (probably too little for a person to detect). Use you own calculations for this question. The lab can be used to test your results by comparing a similar model.

2. Relevant equations

I = E (base eq) / R (base eq);

P (base w) = I^2*R.

I dont know the equation to find the power a light bulb would radiate

in a given electrical circuit.

3. The attempt at a solution

If I hooked a 150 W bulb (about 96 Ohms) to a 2V Battery then:

E (base eq) = 2V

R (base eq) = 96 Ohms.

I = E (base eq) / R (base eq) = 2V / 96 Ohms =~ 0.02080A

0.02080 A is the current that a 150 Watt Light Bulb would draw from a 2V Battery.

To find the power that would dissipate:

P (base w) = I^2*R = (0.02080A)^2 * 150 Ohms =~ 0.06514;

is the amount of power dissipated

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# Homework Help: Equation for the power a light bulb would radiate

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