Equation of a Parabola Passing Through (2,-2√2) Opening to the Right

[Immutef]

Homework Statement

Write the equation of a parabola passing through the point (2,-2√2) and opening to the right.

Homework Equations

Parabola with a horizontal axis and vertex (0,0) y^2 = 4cx

The Attempt at a Solution

Since the parabola opens right I will use the equation y^2 = 4cx
I will let x = 2 and y = -2√2
y^2 = 4c(2)
(-2√2)^2 = 4c(2)
2 = 4c(2)
2 = 8c
1/4 = c
y^2 = 4(1/4)x
y^2 = x

* The answer in my student solution mannual says the correct answer should be y^2 = 4x. When I graph this, my graphs supports this answer, where did I go wrong?

 

[Immutef]

Sorry, I figured it out. When i squared my y value, i only squared the √2, giving me 2, instead of squaring -2√2 which would give 8.