Equation of motion for oscillations about a stable orbit

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SUMMARY

The discussion focuses on deriving the equation of motion for oscillations about a stable orbit, specifically for a planet orbiting the sun with angular momentum L. The effective potential energy equation, Ueff = -Gm1m2/r + L2/(2μr2), is utilized to find the radius of stable orbit and demonstrate stability through the second derivative test, d2U/dr2 > 0. The participant successfully identifies that the period of radial oscillations matches the orbital period, T2 = 4π2μr3/γ, and concludes that the frequency of radial oscillations equals the orbital frequency.

PREREQUISITES
  • Understanding of effective potential energy in orbital mechanics
  • Familiarity with angular momentum in celestial mechanics
  • Knowledge of simple harmonic motion (SHM) principles
  • Ability to perform Taylor expansions in calculus
NEXT STEPS
  • Study the derivation of effective potential energy in gravitational systems
  • Learn about the stability conditions for orbits in celestial mechanics
  • Explore the mathematical formulation of simple harmonic motion
  • Investigate the application of Taylor series in physics for approximating functions
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Astronomy students, physicists, and engineers interested in orbital dynamics and stability analysis of celestial bodies.

Daniel Sellers
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Homework Statement


A) By examining the effective potential energy find the radius at which a planet with angular momentum L can orbit the sun in a circular orbit with fixed r (I have done this already)

B) Show that the orbit is stable in the sense that a small radial nudge will cause only small radial oscillations. [look at d^2U/dr^2] and show that the period of oscillations is equal to the planets orbital period.

Homework Equations


Ueff = -Gm1m2/r + L2/(2μr2)

ω = L/μr2

ϒ = Gm1m2

The Attempt at a Solution


[/B]
It is easy to find the radius of stable orbit:

dU/dt = γ/r2 - L2/(μr3) = 0

r = L2/(γr3)

I can also show that the orbit is stable

d2U/dt2 = γ/r3 > 0 so the radius above is a minimum.

The first derivative being zero also allows me to write

γ = L2/(μr)

which means that

T2 = 4π2μr3

Which matches the equation derived in the text for the period of any bound orbit with constant angular momentum.

The problem! :

I am supposed to find the equation of simple harmonic oscillation in the radial direction, show that the oscillations are small, and show that the period of the radial oscillations is equal to the orbital period. I am at a loss as to how to do this. The last equation which might be relevant is

r(Φ) = 1/(1+εcosΦ) where ε is the eccentricity, which is zero for a circular orbit but obviously not quite zero for a circular orbit that has been given a 'small radial nudge'

I think I have done enough work correctly to get credit for this problem, but I want the correct answer very badly. Can anyone suggest an approach?

Thanks!
 
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Ok I did a little more work with 'the radial equation':

μr⋅⋅ = d/dr(U)

= γ/r2 - L2/μr3

L2 = μ2r4ω2

which implies

r⋅⋅ = γ/r2 - ω2r

Which looks a lot like a differential equation which gives simple harmonic motion except for the γ term.

Now, when dU/dr = 0 which is the condition that I used to find the radius, γ = L2/(μr0) where r0 is the stable orbit radius found in the first part.

So

r⋅⋅ = ω2r2/r0 - ω2r

Soooooo what do I do with this? How do I derive and SHO equation which shows the small oscillations asked for and has the correct period?

Just need someone to point out what I'm missing or give me the last step I think
 
Okay I got it. Start with radial equation and let r = r0 + α where α << r0. Then do a Taylor expansion about r0 and the first derivative of U is zero, the second is known.
You end up with the equation of an oscillator and you can read off the frequency without even solving the differential equation.
Its also true for any SHO that the frequency is equal to the second serivative of potential devided by the mass.

The frequency found for the radial oscillations is equal to the orbital frequency (as is true for all bounded Kepler orbits)

Thanks guys, good talk
 

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