Equation used to find kinetic energy of proton

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SUMMARY

The discussion centers on determining the kinetic energy of a proton given its wavelength, specifically 100 femtometers (fm). Two methods are proposed: Method 1 utilizes the equation λ = h/p, leading to p = sqrt(2Em), while Method 2 employs the relativistic energy-momentum relationship E² = (pc)² + (mc²)². The consensus is that Method 2 is more accurate due to its incorporation of relativistic effects, especially for high-energy particles. The results from Method 1 and Method 2 can differ significantly, highlighting the importance of using the correct approach based on the particle's energy.

PREREQUISITES
  • Understanding of quantum mechanics, specifically wave-particle duality.
  • Familiarity with the Planck constant (h) and its application in quantum equations.
  • Knowledge of relativistic physics, particularly the energy-momentum relationship.
  • Basic proficiency in classical mechanics, including kinetic energy and momentum equations.
NEXT STEPS
  • Study the derivation and application of the relativistic energy-momentum equation E² = (pc)² + (mc²)².
  • Learn about the implications of wave-particle duality in quantum mechanics.
  • Explore the differences between relativistic and non-relativistic kinetic energy calculations.
  • Investigate the significance of units in physics calculations, particularly in energy and momentum.
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Students and professionals in physics, particularly those focusing on quantum mechanics and particle physics, as well as educators teaching the principles of kinetic energy and relativistic effects.

darksyesider
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I am having trouble deciding when to use which equation.

If you're given the wavelength of a proton, let's say 100 fm, and have to find the kinetic energy of it, how would you do this?

Here are my ideas:

Idea 1: Use lambda = h/p, where p = sqrt(2Em).

Idea 2: Use E=(pc)^2+(mc^2)^2 = (mc^2)^2+(h/lambda * c)^2

Then I'll use:

K = E- E_o
==> (answer from idea 1 or 2) - mc^2 Which should I use? I personally think idea 2 is correct because it accounts for the relativisitic effects.

thank you!
 
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In your idea 1 you've already given the wavelength to momentum relationship---and you're given the wavelength. That's all you need.

Edit: looks like I misread the question...
 
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but is the equation correct?
I actually forgot how I got p = sqrt(2Em)...I think I derived it earlier in my work.

Also I asked my friend who is learning this in school and he said that you have to use idea 2 because it is a particle?
 
darksyesider said:
Which should I use? I personally think idea 2 is correct because it accounts for the relativisitic effects.

The relativistic equation is correct in general. Your method 1 is basically non-relativistic, so it's "correct enough" only for low-energy (low-velocity) particles. But it's hard to tell in advance whether the velocity is "low enough" unless you have a lot of experience in doing these kinds of problems. So I would go with your method 2. If you have time, try method 1 also and see how close together the results are.
 
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darksyesider said:
I actually forgot how I got p = sqrt(2Em)

Hint: start with the non-relativistic formulas for momentum and kinetic energy, p = mv and E = (1/2)mv2.
 
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Thank you everyone! My answer using method 2 was actually 1000 times larger than the answer using method 1. I guess you have to take into account relativity!
 
darksyesider said:
My answer using method 2 was actually 1000 times larger than the answer using method 1.

I suggest that you check your calculations and particularly your units carefully. My results for the two methods differ by only about 0.004%.

As a check, calculate the proton's speed assuming the classical formula. What % is it of the speed of light?
 

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