Equations for Calculating Momentum in Pole Vaulting Collisions

  • Thread starter Thread starter StephenDoty
  • Start date Start date
  • Tags Tags
    Physics Sports
StephenDoty
Messages
261
Reaction score
0
Is the collison of the olympic sport polevolting elastic or inelastic? The pole collides with the Earth and stays at that point until the polevolter let's go. So wouldn't you use the momentum equations to see how much momentum the polevolter has once he let's go of the pole?

Which one of the following equations would I use to find the momentum of the polevolter once he has let go of his pole? mv1+mv2=mv1+mv2 or mv1+mv2=(m+m)v

Thank you.

Stephen
 
on Phys.org
StephenDoty said:
So wouldn't you use the momentum equations to see how much momentum the polevolter has once he let's go of the pole?

Hi Stephen! :smile:

It's not a collison … it's exactly like swinging on a rope (but upside down :wink: ).

So you'd just use conservation of energy (including some "spring" energy for the bending of the pole). :smile:
 
so you would have 1/2mv1^2 + 1/2kx^2 +mgh0= 1/2mv2^2 + 1/2kx^2 +mgh1?
 
Yup! :biggrin:
 

Similar threads

Replies
10
Views
7K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
10
Views
3K
  • · Replies 7 ·
Replies
7
Views
7K