1. The problem statement, all variables and given/known data The white ball in the figure has a speed of 1.81 m/s and the yellow ball is at rest prior to an elastic glancing collision. After the collision the white ball has a speed of 1.37 m/s. To the nearest tenth of a degree, measured counterclockwise from east, what angle does it scatter at if the yellow ball is scattered at 280degrees? 2. Relevant equations mv1=mv1'sin(@)+mv2'sin(@) 3. The attempt at a solution (2kg x 1.81m/s) = (2kg x 1.37) sin(@) +(1kg) v2' sin(280) v2': 1/2mv1^2 = 1/2mv1'^2 + 1/2mv2'^2 v2'= 1.67m/s The answer is 37 degrees but I am not sure how to progress from here.