Equations for rotational motion with constant acceleration

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SUMMARY

The discussion focuses on calculating the linear velocity of water expelled from a rotating water pump with a radius of 0.120 m, which accelerates at 35.0 rad/s² for 9.00 seconds. The key equations used include angular acceleration (α = Δω/t) and the relationship between linear and angular velocity (v = rω). After 9 seconds of acceleration, the angular velocity (ω) can be determined, allowing for the calculation of the linear velocity (v) using the pump's radius. This provides a clear method for solving problems related to rotational motion with constant acceleration.

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  • Understanding of angular acceleration and angular velocity
  • Familiarity with linear velocity and its relationship to angular motion
  • Knowledge of basic physics equations related to rotational motion
  • Ability to perform calculations involving radians and time
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A rotating water pump works by taking water in at one side of a rotating wheel, and expelling it from the other side. If a pump with a radius of 0.120 m starts from rest and accelerates at 35.0 rad/s2, how fast will the water be traveling when it leaves the pump after it has been accelerating for 9.00 seconds?
 
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[tex]\alpha[/tex] is measured in radians per second sqared [tex](rad s^{-2} )[/tex] my guess is that you are either trying to find the angular velocity or the linear velocity.

angular acceleration = [tex]\alpha = \frac{\Delta \omega}{t}[/tex]
angular velocity = [tex]\omega = \frac{\Delta \theta}{t}[/tex]

the relationship between linear velocity/acceleration and angular velocity/acceleration is

linear velocity v

radius r

[tex]v= r \omega[/tex] m/s

[tex]a= r \alpha[/tex] m/[tex]s^{2}[/tex]
 

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