Equilibrium constant (K) Question problem

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The discussion revolves around calculating the equilibrium constant (K) for the reaction N2 + 3H2 = 2NH3 using given equilibrium concentrations. The user initially substituted the concentrations into the K expression, resulting in K = 5.6 x 10^8. Concerns were raised about the high value of K, suggesting it should be smaller. Despite the doubts, one participant confirmed that the calculated value is consistent with the provided data. The conversation highlights the importance of verifying calculations in equilibrium chemistry.
Danny523
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Finding the Equilibrium Constant (K)I have been having a bit of trouble with this question, if anyone could guide me on where I am going wrong it would be greatly appreciated!
"Reaction 1: N2 + 3H2 = 2NH3

Write down an expression for the equilibrium constant K, for reaction 1.
At 25 degrees Celsius the equilibrium concentrations of N2, H2 and NH3 gases are:

N2: 1.3 x 10^-3 mol dm^-3
H2: 1.1 x 10^-2 mol dm^-3
NH3: 9.8 x 10^-1 mol dm^-3

Use these values to calculate the value of K at this temperature"So then what I did was substitute these values into this equation:

K = (NH3)^2 / ((N2) x (H2)^3)

To give this:

K = (9.8 x 10^-1)^2 / ((1.3 x 10^-3) x (1.1 x 10^-2)^3)

That then gave me:

K = 5.6 x 10^8

Im pretty sure that is not right, I am thinking it should be a lot lot smaller...

If you could help me out I would appreciate it a lot!

Thanks

Danny
 
Last edited:
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Agreed that value looks high, but that's what you get from the data given.

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